Frictional Torque Flywheel Question

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SUMMARY

The discussion centers on calculating the frictional torque acting on a spinning flywheel with a rotational inertia of 403.8 kg·m², which decelerates from 20.0 rad/s to zero in 256.8 seconds. The user attempted to derive the torque using various physics equations, including the relationship between angular velocity and angular acceleration. The correct approach involves calculating angular acceleration (alpha) and then applying the formula for torque (τ = I * alpha) to find the frictional torque.

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Homework Statement



A spinning flywheel has rotational inertia I = 403.8 kg · m2. Its angular velocity decreases from 20.0 rad/s to zero in 256.8 s due to friction. What is the frictional torque acting?

The Attempt at a Solution



I tried using Vt = r |w| and Wav = change in theta / change in time, to get r, but I'm not sure if that's right,

Then I used I = 1/2mr^2 to get mass.

Finally, I used F=ma to get Force, using the mass found above and acceleration = change in velocity (aka 20*57) / change in time.

Then I had force and radius for plugging into torque = radius*force.
 
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Using w = wo + alpha*t, find alpha.
Torque = I*alpha.
 

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