Frictionless horizontal then ramp?

Click For Summary

Homework Help Overview

The problem involves an object of mass m sliding on a frictionless horizontal surface before encountering a frictionless ramp. The objective is to determine the vertical height the object will reach before coming to rest, utilizing principles of energy conservation.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply the conservation of energy principle, using kinetic energy and potential energy equations. Some participants question the clarity of the terms used in the equations and suggest articulating the principles behind them. Others clarify the definitions of left-hand side (LHS) and right-hand side (RHS) of the equation, prompting further exploration of the potential energy equation.

Discussion Status

The discussion is ongoing, with participants providing clarifications and guidance on the equations involved. There is an acknowledgment of the correct form of the potential energy equation, and some participants express satisfaction with the derived expression for deltaY.

Contextual Notes

Participants are navigating the transition from horizontal motion to vertical motion, which introduces complexity in applying the conservation of energy principle. There is also a focus on ensuring the correct interpretation of the energy equations involved.

conniebear14
Messages
9
Reaction score
0

Homework Statement



An object of mass m and initial speed v0 sliding on a horizontal frictionless surface encounters a frictionless ramp. To what vertical height will the object rise before coming to rest?

Homework Equations



.5mv^2 = .5mgh


The Attempt at a Solution


I used above equation and got (v^2)/g = h
by canceling out .5m on each side. I have no clue if that's right...
 
Physics news on Phys.org
hi conniebear14! :smile:
conniebear14 said:
An object of mass m and initial speed v0 sliding on a horizontal frictionless surface encounters a frictionless ramp. To what vertical height will the object rise before coming to rest?

.5mv^2 = .5mgh

it would help you to get the correct equation if you stated (in words) what principle you are using, or at least what terms you are using

what is the LHS of your equation supposed to be?

what is the RHS of your equation supposed to be? :wink:
 
I don't know what that means (lhs and rhs). That was the only equation I could think of. The horizontal plus a ramp is what is messing me up. Which equations would you recommend?
 
conniebear14 said:
I don't know what that means (lhs and rhs).

left-hand side, right-hand side! (of an equation) :biggrin:

your LHS is the KE, 1/2 mv2

your RHS should be the PE, which is not 1/2 mgh, it's … ? :smile:
 
okay so PE is mgdeltaY?
Where do I go from there?
I set .5mv^2 = mgdeltaY
and got deltaY = (v^2)/2g
 
yes, that looks fine :smile:
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
Replies
5
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 32 ·
2
Replies
32
Views
4K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 6 ·
Replies
6
Views
3K
Replies
3
Views
2K
Replies
10
Views
5K
  • · Replies 5 ·
Replies
5
Views
2K