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Frictionless horizontal then ramp?

  1. Oct 31, 2013 #1
    1. The problem statement, all variables and given/known data

    An object of mass m and initial speed v0 sliding on a horizontal frictionless surface encounters a frictionless ramp. To what vertical height will the object rise before coming to rest?

    2. Relevant equations

    .5mv^2 = .5mgh


    3. The attempt at a solution
    I used above equation and got (v^2)/g = h
    by canceling out .5m on each side. I have no clue if that's right...
     
  2. jcsd
  3. Oct 31, 2013 #2

    tiny-tim

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    hi conniebear14! :smile:
    it would help you to get the correct equation if you stated (in words) what principle you are using, or at least what terms you are using

    what is the LHS of your equation supposed to be?

    what is the RHS of your equation supposed to be? :wink:
     
  4. Oct 31, 2013 #3
    I don't know what that means (lhs and rhs). That was the only equation I could think of. The horizontal plus a ramp is what is messing me up. Which equations would you recommend?
     
  5. Oct 31, 2013 #4

    tiny-tim

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    left-hand side, right-hand side! (of an equation) :biggrin:

    your LHS is the KE, 1/2 mv2

    your RHS should be the PE, which is not 1/2 mgh, it's … ? :smile:
     
  6. Oct 31, 2013 #5
    okay so PE is mgdeltaY?
    Where do I go from there?
    I set .5mv^2 = mgdeltaY
    and got deltaY = (v^2)/2g
     
  7. Oct 31, 2013 #6

    tiny-tim

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    yes, that looks fine :smile:
     
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