From radio signal to corresponding photons

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SUMMARY

The discussion centers on the transmission of a 100 kHz sine signal from a 1-watt transmitter and the assumptions regarding the corresponding photons. It concludes that while classical electrodynamics supports the idea of consistent frequency and intensity of photons, it renders the concept of photons meaningless. In contrast, quantum electrodynamics requires a more detailed specification of the quantum field state to accurately describe the signal, indicating that the initial assumptions do not fully encapsulate the complexities of photon behavior.

PREREQUISITES
  • Understanding of classical electrodynamics principles
  • Familiarity with quantum electrodynamics concepts
  • Knowledge of sine wave signal transmission
  • Basic grasp of photon behavior and properties
NEXT STEPS
  • Study the differences between classical and quantum electrodynamics
  • Learn about the quantum field state and its implications for photon behavior
  • Explore the mathematical representation of sine waves in signal transmission
  • Investigate the concept of intensity and phase in electromagnetic waves
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Physicists, electrical engineers, and students in advanced electromagnetism or quantum mechanics who seek to deepen their understanding of signal transmission and photon behavior.

somega
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Let's assume the following sine signal sent by a low frequency (100 kHz) transmitter.
I think with the information that the sending power is 1 watt and the starting phase is 0 the signal is fully described.

fffMG_0998.JPG

Are the following assumptions correct?:

1. The frequency of all photons leaving the transmitter at any time is 100 kHz.
2. At all points A, B, C, D, E the number of photons leaving the transmitter are the same (this is the intensity).
3. The phase of the photons leaving the transmitter at points A, B, C, D differ.
 
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somega said:
I think with the information that the sending power is 1 watt and the starting phase is 0 the signal is fully described.

If you are using classical electrodynamics, then yes, you're right. But if you are using classical electrodynamics, then the concept of "photon" is meaningless and so are all three of your assumptions.

If you are using quantum electrodynamics, so that the concept of "photon" has meaning (although you still need to specify what meaning you are giving it, since it can have more than one meaning), then the information you give does not fully specify the signal. You need to specify the quantum field state.

So before we can go any further, you need to decide whether you want to use classical electrodynamics or quantum electrodynamics.
 
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