From what height was the ball thrown?

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SUMMARY

The problem involves a ball thrown horizontally at a speed of 24 m/s, covering a horizontal distance of 52 m before hitting the ground. The key to solving this problem lies in separating the velocity into its components, where the horizontal component is 24 m/s and the vertical component is 0 m/s since it is thrown horizontally. Using the kinematic equations, the time taken to hit the ground is calculated to be 2.167 seconds, resulting in a height of 23.01 meters from which the ball was thrown.

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Homework Statement


A ball thrown horizontally at 24m/s travels a horizontal distance of 52 m before hitting the ground. From what height was the ball thrown?


Homework Equations


Kinematic equations


The Attempt at a Solution


I know that the velocity needs to broken into its components. I think the angle is 90 degrees, but I'm not sure. After the components are found, I don't know where to go. I know you're supposed to plug the variable into the y equations to find the time, and then plug the time into the x equation to find displacement or whatever else. But in this problem you're looking for the height in the y direction. I'm just confused.
 
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aligass2004 said:

Homework Statement


A ball thrown horizontally at 24m/s travels a horizontal distance of 52 m before hitting the ground. From what height was the ball thrown?


Homework Equations


Kinematic equations


The Attempt at a Solution


I know that the velocity needs to broken into its components. I think the angle is 90 degrees, but I'm not sure. After the components are found, I don't know where to go. I know you're supposed to plug the variable into the y equations to find the time, and then plug the time into the x equation to find displacement or whatever else. But in this problem you're looking for the height in the y direction. I'm just confused.
Yes, you would need in gneral to break up the velocity into components, but in this problem, it is given that it is thrown horizontally in the x direction, so what is its y component of velocity if it is thrown directly in the horizontal direction? What is its x component of velocity?
 
Ok, so the angle is zero. So is the y component zero and is the x component 24m/s?
 
aligass2004 said:
Ok, so the angle is zero. So is the y component zero and is the x component 24m/s?
Yes. So how long does it take to hit the ground (use the kinematic motion equation in the x direction that relates horizontal distance with horizontal velocity and time). The once you have the time, work on the height.
 
I got it! The time is 2.167, which makes the height 23.01. Thank you soooo much!
 

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