I assume you're referring to the second Friedmann equation, which (in units where G = c = 1, and with zero cosmological constant) looks like this:
[tex]\frac{1}{a} \frac{d^2 a}{dt^2} = - \frac{4 \pi}{3} \left( \rho + 3 p \right)[/tex]
Suppose that at some time [itex]t_0[/itex], which we could call "now"

, we have that [itex]a > 0[/itex] and [itex]da /dt > 0[/itex]. This says that the Universe has some nonzero "size" (the scale factor a is a measure of "how large" the Universe is, though there are some technicalities with that that we probably don't need to get into here), and that it is expanding--i.e., to the future of [itex]t_0[/itex], a(t) will increase.
Now follow the history of the Universe into the past, given those conditions at [itex]t_0[/itex]. In the past direction, the Universe is contracting; and if [itex]\rho + 3 p[/itex] is positive, then [itex]d^2 a / dt^2[/itex] is negative, meaning that as we go into the past, the contraction of the universe "accelerates". That is enough to ensure that at some finite time in the past, we will reach a = 0, which is the Big Bang singularity.