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Full-Wave Bridge Rectifier Filter + Regulator DC Power supply

  1. Jul 4, 2009 #1
    http://img104.imageshack.us/img104/3557/1234uyq.jpg [Broken]

    Ok, there are a few calculations on this problem that I am having difficulty with. This is a past homework assignment which is why the answers are filled in. They are all correct.

    Anyways I approached the problem in this manner:

    V secondary peak = V2/ .707

    The voltage drop across RL is ZZT

    IRL= ZZT/RL

    VC1P= V2P - Both forward biased diode drops.

    VC1 P-P (Ripple) = IDC / (2f * C)

    VRS= Vc1 dc - Vzt

    IRS= VRS /RS


    The three that I am having trouble with are: Vc1-dc , IZ, and VRL p-p (Ripple)

    Can anyone help me out?

    Thanks.
     
    Last edited by a moderator: May 4, 2017
  2. jcsd
  3. Jul 5, 2009 #2
    Update>>>>>>>>>>>>>>>>>>>>>


    Now all I need to know its how to find the value of. Vc-dc
     
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