Fundemental theorem of Calc. question?

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The discussion centers on solving the equation involving the integral of a function f(t) divided by t², specifically finding f(x) and a constant a such that 6 + ∫(f(t)/t²) dt from a to x equals 2x. The solution identifies a as 3, leading to the function f(x) = 2x² - 6. Participants emphasize the importance of correctly applying the Fundamental Theorem of Calculus and taking derivatives accurately, particularly noting that the derivative of a constant, such as 6, is zero.

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Homework Statement


Find function f(x) and constant a such that,

6+ integral f(t)/t^2 dt = 2x
limits are a to x

Homework Equations


I think I am on the right track could someone check this?

The Attempt at a Solution


if x = a then the integral will = 0,
6 = 2a, a = 3 limits now are 3 to x,
now,
6 + integral f(x)/x^2 dx = 2x, fundamental theorem
6 + f(x)/x^2 = 2 => 6 + f(x)= 2x^2 => f(x)= 2x^2 - 6
Thanks!
 
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try to take the derivative of both sides and see what happens?
on your last line, when you took the derivative, you missed something. what is the derivative of 6?
 
Ok thanks that was the part I was not sure about so the derivative of 6 goes to 0.
Thanks!
 

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