What is the Galois group of x^p - 2 for a prime p?

  • Thread starter Thread starter Mystic998
  • Start date Start date
  • Tags Tags
    Group Polynomial
Click For Summary
SUMMARY

The Galois group of the polynomial x^p - 2, where p is a prime, is determined to have an order of p(p-1). The discussion outlines the field extensions Q ⊆ Q(ζ) ⊆ Q(ζ,√[p]{2}) and Q ⊆ Q(ζ^n√[p]{2}) ⊆ Q(ζ,√[p]{2}), where ζ is a primitive pth root of unity. The analysis suggests that understanding semidirect products is crucial for further exploration of the Galois group structure, particularly for specific primes like p = 5.

PREREQUISITES
  • Understanding of Galois theory and field extensions
  • Familiarity with primitive roots of unity, specifically pth roots
  • Knowledge of semidirect products in group theory
  • Basic algebraic number theory concepts
NEXT STEPS
  • Explore the structure of semidirect products in Galois groups
  • Investigate the Galois group of x^5 - 2 as a specific case
  • Study the implications of the order of Galois groups on field extensions
  • Learn about the application of cyclotomic fields in Galois theory
USEFUL FOR

Mathematicians, particularly those specializing in algebra, number theory, and Galois theory, will benefit from this discussion, as well as students tackling advanced topics in field theory.

Mystic998
Messages
203
Reaction score
0

Homework Statement



Okay, I'm trying to explicitly determine the Galois group of x^p - 2, for p a prime.

Homework Equations





The Attempt at a Solution



Okay, so what I've come up with is that I'm going to have extensions \textbf{Q} \subset \textbf{Q}(\zeta) \subset \textbf{Q}(\zeta,\sqrt[p]{2}) and \textbf{Q} \subset \textbf{Q}(\zeta^{n}\sqrt[p]{2}) \subset \textbf{Q}(\zeta,\sqrt[p]{2}), where 0 \leq n \leq p-1, and \zeta is a primitive pth root of unity. Using that information, I was able to come up with the fact that the Galois group has order p(p-1), but I can't really do much beyond that. I'm going to try figuring it out for p = 5 just to see if it's instructive, but in the meantime suggestions would be appreciated.
 
Physics news on Phys.org
Hint: Think semidirect products.
 

Similar threads

Replies
15
Views
4K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 19 ·
Replies
19
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 28 ·
Replies
28
Views
5K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
13
Views
2K