Gas Chromatography: Example of Molar Proportion of A & B

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SUMMARY

The discussion centers on the principles of gas chromatography (GC) and the quantification of substances A and B based on the areas under their respective peaks. It is established that the areas are directly proportional to the molar amounts of each substance, meaning that if the number of moles of a substance doubles, the area under its peak also doubles. The relationship between peak area and molar amount can vary depending on the specific compounds analyzed, with larger molecules typically producing greater peak areas due to increased heat release during combustion. The internal standard technique, often utilizing substances like tridecane, is recommended for accurate quantification.

PREREQUISITES
  • Understanding of gas chromatography (GC) principles
  • Knowledge of peak area quantification in chromatography
  • Familiarity with combustion analysis techniques
  • Experience with internal standard methods in analytical chemistry
NEXT STEPS
  • Research the internal standard technique in gas chromatography
  • Learn about combustion analysis methods for GC
  • Explore the effects of molecular weight on peak area in chromatography
  • Investigate the use of tridecane as an internal standard in quantification
USEFUL FOR

Chemists, analytical laboratory technicians, and students studying gas chromatography and quantitative analysis techniques will benefit from this discussion.

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what does it mean when it says; "the areas under the two peaks are directly proportional to the molar amounts of A and B in the mixture?


directly proportional? can anyone give an example of it?

many thanks!
 
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If the number of moles of substance doubles, the area under the peak will double too. By analyzing the area under the peak, you can quantitate the relative amounts of A and B in the mixture.
 
Depending on the type of analyzer you have on your GC instrument, this won't necessarily be a 1:1 relationship between two different compounds. The relationship for each individual compound is proportional to the number of moles of that compound. Typically GCs use a combustion analysis to measure what is coming off of the column. Therefore, the area under the peak will depend on the particular molecule that is being combusted; in general larger molecules will give a greater peak area because more heat is released in their combustion. The way to solve this problem is to make a 1:1 mixture of two compounds and measure the areas you get from the GC trace of the mixture. Then, since you know that there was an equal number of moles of each compound, you can figure out the proportion that relates the area of the two peaks. This can allow you to calculate the yield of your reaction based just on the GC trace!

Note that in most cases you can assume that the relation between the two different compounds is 1:1, but if you want precise results you should figure out the relation I described.

I bet this sounds complicated. Sorry if I didn't explain it very well.
 
Movies has explained this greatly, but I wanted to add this one. "Internal standard technique" is frequently used for quantification, in which a known amount of substance is added and whose peak is known to occur far from the analyte peaks. So, comparing the peak areas with analyte peaks, a quantification is very easy to calculate.
 
Chem_tr makes a good point. When using internal standards it is also important that the internal standard be unreactive under the conditions of the reaction you are monitoring. High molecular weight n-alkanes are therefore good for this purpose. I frequently use tridecane.
 

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