Gas expansion at constant pressure

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SUMMARY

The discussion focuses on the gas expansion of 2 moles of a monatomic ideal gas at constant pressure and adiabatically. Initially, the gas occupies a volume of 0.02 m³ at 300 K and expands to 0.04 m³, resulting in a temperature of 600 K. The final volume after adiabatic cooling back to 300 K is determined to be 0.061 m³. The heat supplied during the process is calculated to be 5 kJ, which corresponds to the work done on the gas, as the adiabatic process from state 2 to state 3 involves no heat transfer.

PREREQUISITES
  • Understanding of the Ideal Gas Law (PV = nRT)
  • Knowledge of adiabatic processes and the relationship between temperature and volume (TV^{\gamma-1})
  • Familiarity with specific heat capacity at constant pressure (cp)
  • Concept of internal energy change for ideal gases
NEXT STEPS
  • Research the derivation and application of the Ideal Gas Law (PV = nRT)
  • Study the principles of adiabatic processes and the equation TV^{\gamma-1}
  • Learn about specific heat capacities for monatomic gases and their implications in thermodynamic calculations
  • Explore the relationship between work done and heat transfer in thermodynamic systems
USEFUL FOR

Students studying thermodynamics, engineers working with gas systems, and anyone interested in understanding gas behavior under varying pressure and temperature conditions.

wavingerwin
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Homework Statement


2 moles of gas at 300 K at 0.02 m3 is expanded to twice the original volume at constant pressure, and then adiabatically until T = 300 K again.

assume monatomic gas. assume ideal.

determine the final volume

determine the heat supplied to the overall process

determine change in internal energy

Homework Equations


PV = nRT
TV^{\gamma-1} = TV^{\gamma-1}

The Attempt at a Solution


State 1
n = 2
V = 0.02
R = 8.31
T = 300

P = 249.3 kPa

State 2
P = 249.3
V = 0.04

T = 600 K

State 3
T = 300
monatomic therefore \gamma=5/3

V = 0.061

so final volume is 0.061 m3

I am struggling to find the "heat supplied" to the system. Since from state 2 to 3 the process is adiabatic, Q = 0.

So the only heat transfer occur from state 1 to 2.

Would it just be equal to the work?
so Q = W = P(V2-V1) = 249300 x 0.02 = 5 kJ?

and so the change in internal energy must also be be 5 kJ?

thank you in advance.
 
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How can you make the gas expand at constant pressure?

ehild
 
Hi ehild

by applying heat and raising its temperature.

However, I don't have/know an equation that equates total heating applied (Q) to the raise in temperature..
 
What about specific heat capacity at constant pressure?

ehild
 
specific heat, c would equal du/dT

so I guess the heat supplied, q, would equal change in u = c dT

but c is not given in the question.
 
It is 2 moles of mono-atomic ideal gas. Look after cp.

ehild
 

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