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Gas in tank exposed to a vacuum

  1. Mar 15, 2012 #1
    1. The problem statement, all variables and given/known data
    A tank is equally divided into two equal halves, one a vacuum and one filled with argon gas at 298K and 700 bar. The divider bursts and the gas equally disperses throughout the tank. What is the new T and P of the gas assuming argon is an ideal gas?


    2. Relevant equations
    PV=nRT P1V1/T1=P2V2/T2


    3. The attempt at a solution
    I assumed there was no temperature change which I am unsure of but using that logic, P=350 bar and T=298K
     
  2. jcsd
  3. Mar 16, 2012 #2

    rude man

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    Begin with the definiton of an ideal gas. Hint: it's more than just pV = nRT.
    What can you say about the dependence of U, internal energy, as a function of p,V and/or T?
    Then go with the first law and show that you get the same results whether the free expansion is adiabatic or isothermal or anything inbetween.
     
  4. Mar 16, 2012 #3

    rude man

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    You can't make that assumption unless you can prove it.

    Begin with the definiton of an ideal gas. Hint: it's more than just pV = nRT.

    What can you say about the dependence of U, internal energy, as a function of p,V and/or T?

    Then go with the first law and determine if you get the same results whether the free expansion is adiabatic or isothermal or anything inbetween.
     
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