Gas in tank exposed to a vacuum

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SUMMARY

The discussion centers on the thermodynamic behavior of argon gas in a tank divided into a vacuum and gas-filled section. When the divider bursts, the gas expands to fill the entire volume, resulting in a new pressure of 350 bar and a temperature of 298K, assuming ideal gas behavior. The participants emphasize the importance of not assuming constant temperature without proof and highlight the relevance of the first law of thermodynamics in analyzing the process, whether it is adiabatic or isothermal.

PREREQUISITES
  • Understanding of ideal gas laws, specifically PV=nRT
  • Knowledge of the first law of thermodynamics
  • Familiarity with concepts of adiabatic and isothermal processes
  • Basic principles of internal energy (U) as a function of pressure, volume, and temperature
NEXT STEPS
  • Study the implications of free expansion in thermodynamics
  • Learn about the derivation and applications of the first law of thermodynamics
  • Explore the behavior of real gases versus ideal gases under varying conditions
  • Investigate the relationship between internal energy, pressure, volume, and temperature in thermodynamic systems
USEFUL FOR

Students and professionals in thermodynamics, chemical engineering, and physics who are analyzing gas behavior in vacuum systems and understanding the principles of ideal gas laws and thermodynamic processes.

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Homework Statement


A tank is equally divided into two equal halves, one a vacuum and one filled with argon gas at 298K and 700 bar. The divider bursts and the gas equally disperses throughout the tank. What is the new T and P of the gas assuming argon is an ideal gas?


Homework Equations


PV=nRT P1V1/T1=P2V2/T2


The Attempt at a Solution


I assumed there was no temperature change which I am unsure of but using that logic, P=350 bar and T=298K
 
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Begin with the definition of an ideal gas. Hint: it's more than just pV = nRT.
What can you say about the dependence of U, internal energy, as a function of p,V and/or T?
Then go with the first law and show that you get the same results whether the free expansion is adiabatic or isothermal or anything inbetween.
 
GZunich said:

Homework Statement


A tank is equally divided into two equal halves, one a vacuum and one filled with argon gas at 298K and 700 bar. The divider bursts and the gas equally disperses throughout the tank. What is the new T and P of the gas assuming argon is an ideal gas?


Homework Equations


PV=nRT P1V1/T1=P2V2/T2


The Attempt at a Solution


I assumed there was no temperature change which I am unsure of but using that logic, P=350 bar and T=298K

You can't make that assumption unless you can prove it.

Begin with the definition of an ideal gas. Hint: it's more than just pV = nRT.

What can you say about the dependence of U, internal energy, as a function of p,V and/or T?

Then go with the first law and determine if you get the same results whether the free expansion is adiabatic or isothermal or anything inbetween.
 

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