Gauss-jordan 3 equation matrix help

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Homework Help Overview

The discussion revolves around solving a system of linear equations represented in matrix form. Participants are working through the Gauss-Jordan elimination method to find the solution to the equations.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants share their attempts at row reduction and express confusion over discrepancies in their results compared to expected solutions. Questions arise regarding specific row operations and the validity of certain steps taken during the process.

Discussion Status

There is an ongoing examination of the row reduction steps, with some participants questioning the correctness of the original matrix setup. Guidance is being offered to clarify where mistakes may have occurred, and there is an acknowledgment of potential typographical errors in the problem statement.

Contextual Notes

Participants note that the original matrix may have been misstated, which could affect the validity of the solutions being discussed. The conversation includes a query about the legitimacy of dividing a row by itself as part of the row operations.

bdh2991
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Homework Statement



the original problem is in matrix form:

1 1 2 8
-1 -2 -3 1
3 -7 4 10

Homework Equations





The Attempt at a Solution



i got all the way to :

1 1 0 -4
0 1 0 1
0 0 1 2

however, the top row is supposed to = 3 but when i subtract row 2 from row 1 i get -5...i can't find where i messed up in the steps i did it. anyone get the same thing as me or know what i did wrong?
 
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bdh2991 said:

Homework Statement



the original problem is in matrix form:

1 1 2 8
-1 -2 -3 1
3 -7 4 10

Homework Equations





The Attempt at a Solution



i got all the way to :

1 1 0 -4
0 1 0 1
0 0 1 2
I don't know what you did to get the matrix above, but it's incorrect. This says that y = 1 and z = 2. From these you can work back to get x.

In any case, these values are incorrect. I've worked through the row reduction, and have a solution, which I have checked, so I know it's right.

Can you show what work you did to get the above? From that, we can tell you where you went astray.
bdh2991 said:
however, the top row is supposed to = 3 but when i subtract row 2 from row 1 i get -5...i can't find where i messed up in the steps i did it. anyone get the same thing as me or know what i did wrong?
 
Mark44 said:
I don't know what you did to get the matrix above, but it's incorrect. This says that y = 1 and z = 2. From these you can work back to get x.

In any case, these values are incorrect. I've worked through the row reduction, and have a solution, which I have checked, so I know it's right.

Can you show what work you did to get the above? From that, we can tell you where you went astray.

that's weird because the book answer says that x = 3, y = 1, and z = 2, which is why i thought i only got the top row part wrong. the operations i used were:

row 2 * -1 minus row 1

row 3 minus 3 * row 1

10 * row 2 + row 3

row 3 / -52

5 * row 3 plus row 2

2 * row 3 minus row 1

row 2 minus row 1
 
bdh2991 said:
that's weird because the book answer says that x = 3, y = 1, and z = 2
That is not a solution to the problem you posted.
The augmented matrix you posted is
1 1 2 8
-1 -2 -3 1
3 -7 4 10

The book solution works in the 1st and 3rd equations, but it doesn't work in the 2nd equation.

-1(3) -2(1) -3(2) = -3 -2 -6 = -11 ≠ 1

There are a couple of possibilities. It might be that you mistyped the original matrix. If the 2nd row was actually -1 -2 -3 11[/color], then the book's answer is correct.


Otherwise, the book's answer is wrong.
bdh2991 said:
, which is why i thought i only got the top row part wrong. the operations i used were:

row 2 * -1 minus row 1

row 3 minus 3 * row 1

10 * row 2 + row 3

row 3 / -52

5 * row 3 plus row 2

2 * row 3 minus row 1

row 2 minus row 1
 
Mark44 said:
That is not a solution to the problem you posted.
The augmented matrix you posted is
1 1 2 8
-1 -2 -3 1
3 -7 4 10

The book solution works in the 1st and 3rd equations, but it doesn't work in the 2nd equation.

-1(3) -2(1) -3(2) = -3 -2 -6 = -11 ≠ 1

There are a couple of possibilities. It might be that you mistyped the original matrix. If the 2nd row was actually -1 -2 -3 11[/color], then the book's answer is correct.Otherwise, the book's answer is wrong.
You are correct, i accidentally put a -3 in the second row when it should have been a 3. My apologies to everyone. Also, is it a valid row operation to divide a row by itself?
 
Last edited:

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