Gauss' Law between infinite plates

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SUMMARY

This discussion focuses on applying Gauss' Law to calculate the electric field and potential difference between two infinite plates with a uniform charge density, denoted as ##\rho##. The electric field inside the plates is determined to be ##2\pi \rho x## in CGS units, while the direction of the electric field is established based on symmetry and the sign of the charge density. The conversation emphasizes the importance of Gaussian surfaces and the influence of induced surface charges when analyzing regions outside the plates.

PREREQUISITES
  • Understanding of Gauss' Law and its application in electrostatics
  • Familiarity with electric field concepts and charge density
  • Knowledge of symmetry in physics problems
  • Basic proficiency in using Gaussian surfaces for field calculations
NEXT STEPS
  • Study the derivation of electric fields using Gauss' Law in various configurations
  • Learn about induced surface charges and their effects on electric fields
  • Explore Poisson's equation as an alternative method for solving electrostatic problems
  • Convert electric field calculations from CGS to SI units for practical applications
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Students and educators in physics, particularly those studying electrostatics, as well as anyone seeking to deepen their understanding of electric fields and Gauss' Law applications in theoretical scenarios.

flintbox
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Homework Statement


The volume between two infinite plates located at x=L and x=-L respectively is filled with a uniform charge density ##\rho##. Calculate the electric field in the regions above, between and below the plates. Calculate the potential difference between the points x=-L and x=L.

Homework Equations

& attempt[/B]
I want to apply Gauss' Law, but I don't know how to. To me it seems that inside the plates, the charge enclosed is that of any surface, but I wouldn't know the flux of the electric field. I tried searching literature, but they all consider charged plates, whereas here, the plates are just boundaries.
 
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Hint: Take advantage of symmetry. Imagine a Gaussian surface in the shape of a cube centered at x = 0.
 
Doc Al said:
Hint: Take advantage of symmetry. Imagine a Gaussian surface in the shape of a cube centered at x = 0.
But I am confused about the direction of the electric field inside the plates, since there is a charge density everywhere.
 
flintbox said:
But I am confused about the direction of the electric field inside the plates, since there is a charge density everywhere.
Other hint: consider any point exactly midway between the two plates, what can you say about the E field there?

Now, consider another point between the two plates but not exactly midway this time. You should be able to tell what the direction of the E field is, there. Using only the symmetry of the problem (consider the plates to be infinite).
 
flintbox said:
But I am confused about the direction of the electric field inside the plates, since there is a charge density everywhere.
Take ##\rho## as positive. All that matters in the charge within your Gaussian surface. If the charge enclosed is positive, which way must the field point?
 
nrqed said:
Other hint: consider any point exactly midway between the two plates, what can you say about the E field there?

Now, consider another point between the two plates but not exactly midway this time. You should be able to tell what the direction of the E field is, there. Using only the symmetry of the problem (consider the plates to be infinite).
The E field just above the center points upward and the E field below downwards. Thank you! I think I can do it now.
 
Doc Al said:
Take ##\rho## as positive. All that matters in the charge within your Gaussian surface. If the charge enclosed is positive, which way must the field point?
Then the field points outwards! Thanks
 
Careful with the Gaussian surfaces! In addition to the volume charges there are also induced surface charges!

(This problem is also easily solved by solving Poisson's equation.)
 
I've used Gauss to determine the Electric field inside to be ##2\pi \rho x## (CGS units), but what about outside? I don't know how to apply Gauss since there is no charge enclosed.
 
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  • #10
flintbox said:
I don't know how to apply Gauss since there is no charge enclosed.
If a Gaussian surface extends beyond the plates, then it encloses the charge between them.
 
  • #11
flintbox said:
I've used Gauss to determine the Electric field inside to be $2\pi \rho x$ (CGS units), but what about outside? I don't know how to apply Gauss since there is no charge enclosed.
I can't read your post and I'd have to convert to SI.
Run a surface from inside one of the plates to any outside region. Remember what I said about surface charges ...
 

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