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Gauss' Law - Electric Field for a Charged Metal Plate
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[QUOTE="Gustavo, post: 5746369, member: 619637"] [h2]Homework Statement [/h2] An infinite metal plate has a surface density of charge σ[SUB]L[/SUB]=-6μC/m² , Left side and a surface density Of load σ[SUB]R[/SUB]=+4μC/m² , in the right side. A Gaussian surface In the form of a circular cylinder, with area A 12 cm², is Located with the left side inside the plaque and a thin Plate loaded to the right. The surface charge density of the Metal plate is σ[SUB]A[/SUB]. Check the correct option with respect to the density value Superficial σ[SUB]A[/SUB] And flow Φ[SUB]E[/SUB] Through the Gaussian. [ATTACH=full]196324[/ATTACH] ANSWER: D [h2]Homework Equations[/h2] Gauss law for an infinite plate: E=|σ|/2ε[SUB]0[/SUB] [h2]The Attempt at a Solution[/h2] I could not understand the problem, I do not know how to find the density and nor the flow. I tried to use Gauss's Law but I could not understand the problem. [/QUOTE]
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Gauss' Law - Electric Field for a Charged Metal Plate
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