MHB Gay-Lussac's Law of combining volumes

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The discussion confirms that the reaction of 50 cm³ of nitrogen with 150 cm³ of hydrogen to produce 100 cm³ of ammonia aligns with Gay-Lussac's Law of combining volumes. According to this law, the volumes of gases involved in a chemical reaction are in simple ratios that correspond to the ratios of their molecular quantities. In this case, the ratio of nitrogen to hydrogen to ammonia is 1:3:2, which matches the provided volumes. Thus, the formation of 100 cm³ of ammonia from the given gases is consistent with Gay-Lussac's principles. The conclusion is that the reaction adheres to the law as expected.
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50 cm^3 of nitrogen combine with 150 cm^3 of hydrogen gas to form 100 cm^3 of ammonia. Does this agree with gay lussacs law of combing volumes?. Explain your answer.

i feel the answer is yes but I can not give the reason why?
 
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markosheehan said:
50 cm^3 of nitrogen combine with 150 cm^3 of hydrogen gas to form 100 cm^3 of ammonia. Does this agree with gay lussacs law of combing volumes?. Explain your answer.

i feel the answer is yes but I can not give the reason why?

The reaction is:
$$\ce{N2 + 3H2 \to 2NH3}$$

Gay-Lussac says that the ratio of molecules corresponds to the ratio of volumes of gasses.
That is:
$$1:3:2 = 50 \text{ cm}^3 : 150 \text{ cm}^3 : 100 \text{ cm}^3$$
Therefore the $100 \text{ cm}^3$ of ammonia does indeed agree with Gay-Lussac's law.
 
I like Serena said:
The reaction is:
$$\ce{N2 + 3H2 \to 2NH3}$$

Gay-Lussac says that the ratio of molecules corresponds to the ratio of volumes of gasses.
That is:
$$1:3:2 = 50 \text{ cm}^3 : 150 \text{ cm}^3 : 100 \text{ cm}^3$$
Therefore the $100 \text{ cm}^3$ of ammonia does indeed agree with Gay-Lussac's law.
thank you very much
 
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