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## Main Question or Discussion Point

Hi,

I want to calculate the amount of liquid nitrogen (at boiling temp.) needed to build a pressure of 10.1 bar in a vessel of volume 66 m

Given that the molar mass is m = 14.0067 g/mol, we get a total mass of M = 378 kg. The density of liquid nitrogen at boiling temp. is 0.808 kg/l, so this gives the needed amount 468 liters.

Is this reasonable, or are there any major flaws in the calculation?

Thanks

I want to calculate the amount of liquid nitrogen (at boiling temp.) needed to build a pressure of 10.1 bar in a vessel of volume 66 m

^{3}. The liquid will be poured slowly into the vessel, boil off and fill the volume with gas at the specified pressure. I make the assumption that the process is isothermal (T = 300 K); is this a valid assumption? If so, the ideal gas law gives that the needed amount of N_{2}is n ≈ 27000 moles.Given that the molar mass is m = 14.0067 g/mol, we get a total mass of M = 378 kg. The density of liquid nitrogen at boiling temp. is 0.808 kg/l, so this gives the needed amount 468 liters.

Is this reasonable, or are there any major flaws in the calculation?

Thanks