General Launch Angle (Vectors) HELP

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Homework Help Overview

The problem involves projectile motion, specifically analyzing the trajectory of a handball hit at an angle. The original poster seeks assistance with calculating the time of flight, height at impact, and the velocity vector upon hitting a wall.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster has calculated the time to reach the wall and the height at impact but is uncertain about determining the direction of the velocity vector. Some participants suggest calculating the horizontal and vertical components of the velocity separately.

Discussion Status

Participants are engaging in a constructive dialogue, with some providing guidance on how to approach the calculation of velocity components. There is an ongoing exploration of the concepts involved, particularly regarding the effects of gravity on vertical motion.

Contextual Notes

The original poster mentions a time constraint due to an upcoming quiz, which may influence the urgency of the discussion. There is also a reference to previously established equations for vector magnitude and direction.

baseketballr09
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General Launch Angle (Vectors) PLZ HELP URGENT

Homework Statement



In a friendly game of handball, you hit the ball essentially at ground level and send it toward the wall witha speed of 13m/s at an angle of 24 degrees above the horizontal. a) how long does it take for the ball to reach the wall if it is 4.2m away? b) how high is the ball when it hits the wall? c) what are the magnitude and direction of the ball's velocity when it strikes the wall?

Homework Equations



magnitude - vector A is A = (square root Ax^2 + Ay^2)
direction- vector A is theta = inverse tangent (Ay/Ax), theta is measured relative to x axis.

The Attempt at a Solution



I have already done a) .35 seconds and b) 1.36 meters... for c) i got the magnitude which is 12 m/s but i am clueless on how to get direction...somebody please help I'm lost and i have tried my best not to mention i have a quiz on this stuff in four hours...
 
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You have already written down how to to find the direction of a vector in terms of Ay and Ax.

Find vx and vy at the wall.
 
how might i go about doing that please?
 
Calculate vx and vy separately. vx remains constant beacuse there's no force in the horizontal direction. vy changes due to gravity acting down ward. So,
vy_final^2 = vy_initial^2 -2gh.
 

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