General physics problem involving velocity, acceleration, braking of a car

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SUMMARY

The discussion focuses on a physics problem involving a car's velocity, acceleration, and braking to determine whether to stop or continue driving when faced with a yellow traffic signal. The initial speed is 55 km/h (15.28 m/s), with a deceleration rate of 5.18 m/s² and a reaction time of 0.75 seconds. Two scenarios are analyzed: one with a distance of 40 m and a yellow light duration of 2.8 seconds, and another with 32 m and 1.8 seconds. The conclusion hinges on calculating the total distance traveled before and during deceleration to ascertain the appropriate action.

PREREQUISITES
  • Understanding of kinematic equations, specifically the equation x = x0 + v0 t + 0.5at²
  • Knowledge of unit conversion from km/h to m/s
  • Familiarity with concepts of reaction time and its impact on motion
  • Basic principles of acceleration and deceleration in physics
NEXT STEPS
  • Calculate the total stopping distance using the formula for distance covered during deceleration.
  • Explore the implications of reaction time on stopping distance in driving scenarios.
  • Investigate the effects of varying deceleration rates on stopping distances.
  • Learn about traffic signal timing and its relationship to vehicle stopping distances.
USEFUL FOR

This discussion is beneficial for physics students, driving instructors, traffic safety analysts, and anyone interested in understanding the dynamics of vehicle motion in relation to traffic signals.

munchy35
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1.

You are driving toward a traffic signal when it turns yellow. Your speed is the legal speed limit of v0=55 km/h.: your best deceleration rate has the magnitude a = 5.18 m/s^2. Your best reaction time to begin braking is T = .75S. To avoid having the front of your car enter the intersection after the light turns red, should you brake to a stop or continue to move at 55 km/h if the distance to the intersection and the duration of the yellow light are a) 40 m and 2.8 s, and b) 32 m and 1.8s? Give an answer of brake, continue, either (if either strategy works) or neither (if neither strategy works and the yellow duration is inappropriate).

2.
x = x0 + v0 t + .5at^2

any derivatives needed...dx/dt? dv/dt?


3.

well the first thing i tried was converting the 55 km/h to the correct units of m/s. so 55 km/h = roughly about 15.277778 m/s.

then i drew some pictures and realized i need to use a formula involving v0, time, distance, and acceleration. I'm just confused on how to use T=.75 s. I'm getting a physics tutor soon, but since i don't have one yet...i need a lot of help. i just don't even know where to begin.
 
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This is similar to another question I saw here yesterday.
It's a two-part problem since the car doesn't begin to decelerate until the driver reacts. That's where the 0.75s comes in.

total distance traveled = distance covered before reaction + distance covered during deceleration
 

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