Deceleration, velocity, acceleration, distance

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SUMMARY

This discussion focuses on the physics of deceleration, velocity, acceleration, and distance in the context of a vehicle approaching a traffic signal. The scenario involves a car traveling at a speed of 55 km/h (15.28 m/s) with a deceleration rate of 5.18 m/s² and a reaction time of 0.75 seconds. Participants analyze two situations: one with a distance of 40 m and a yellow light duration of 2.8 seconds, and another with 32 m and 1.8 seconds. The consensus is to calculate whether braking or continuing at the current speed is the optimal strategy to avoid entering the intersection after the light turns red.

PREREQUISITES
  • Understanding of basic kinematics equations, specifically x = x0 + v0 t + 0.5at²
  • Knowledge of unit conversion from km/h to m/s
  • Familiarity with concepts of acceleration and deceleration
  • Basic understanding of reaction time in driving scenarios
NEXT STEPS
  • Calculate stopping distance using the formula for deceleration and reaction time
  • Explore the implications of different reaction times on stopping distance
  • Learn about the physics of motion under constant acceleration
  • Investigate real-world applications of kinematics in traffic safety
USEFUL FOR

Students studying physics, driving instructors, traffic safety analysts, and anyone interested in the practical applications of kinematics in driving scenarios.

munchy35
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1.

You are driving toward a traffic signal when it turns yellow. Your speed is the legal speed limit of v0=55 km/h.: your best deceleration rate has the magnitude a = 5.18 m/s^2. Your best reaction time to begin braking is T = .75S. To avoid having the front of your car enter the intersection after the light turns red, should you brake to a stop or continue to move at 55 km/h if the distance to the intersection and the duration of the yellow light are a) 40 m and 2.8 s, and b) 32 m and 1.8s? Give an answer of brake, continue, either (if either strategy works) or neither (if neither strategy works and the yellow duration is inappropriate).

2.
x = x0 + v0 t + .5at^2

any derivatives needed...dx/dt? dv/dt?


3.

well the first thing i tried was converting the 55 km/h to the correct units of m/s. so 55 km/h = roughly about 15.277778 m/s.

then i drew some pictures and realized i need to use a formula involving v0, time, distance, and acceleration. I'm just confused on how to use T=.75 s. I'm getting a physics tutor soon, but since i don't have one yet...i need a lot of help. i just don't even know where to begin.
 
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I believe you can use the reaction time to calculate the distance you travel before applying the brake. You should be able to find the answer if you just use the equation you have quoted I don't think derivatives are required.:biggrin:
 

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