General question about continuity (2 var.)

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SUMMARY

The discussion confirms that if fx(x0, y0) exists, then the function g(x) = f(x, y0) is continuous at x = x0. This is established by recognizing that g(x) is effectively a function of a single variable, x, with y0 held constant. The continuity of g(x) can be analyzed using the principles of single-variable calculus, specifically focusing on the behavior of derivatives and limits.

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tmlfan_17
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You know that fx(x0,y0) exists. What can you tell about the continuity of g(x)=f(x, y0) at x=x0?

I know the answer is that it is continuous but I just wanted somebody to confirm why.
 
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Since yo is fixed, you simply have a function of one variable (x), so apply what you know about a function of one variable and its derivative.
 

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