General Relativity & Differential Geometry Q&A

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SUMMARY

This discussion focuses on the application of differential geometry in general relativity, specifically regarding the metric tensor on a 2-sphere. It establishes that while the spherical coordinate system (theta, phi) can cover the entire sphere, the metric tensor's representation is discontinuous at the Greenwich Meridian. The conversation concludes that multiple charts are necessary to accurately represent the metric tensor, with each chart having its own distinct metric formula derived from the coordinate transformations.

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  • Understanding of general relativity principles
  • Familiarity with differential geometry concepts
  • Knowledge of metric tensors and their properties
  • Experience with coordinate transformations in mathematical physics
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  • Study the concept of coordinate charts in differential geometry
  • Learn about the transformation of metric tensors between different coordinate systems
  • Explore the implications of discontinuities in metric representations
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This discussion is beneficial for physicists, mathematicians, and students studying general relativity and differential geometry, particularly those interested in the intricacies of metric tensors and coordinate systems.

shereen1
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Dear all
I am studying general relativity and i have a question as follow. We have the 2- sphere can be scanned totally by a coordinate system (theta, phi) with the metric tensor written in terms of theta and phi. Now i want to divide the 2-sphere into charts 4 charts then each will have its own coordinate system. Then what will happen for the metric? initially we were having the same formula for the metric for the whole sphere but now shall i say that each chart will have its own metric formula?
Thank you
 
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I think that, although the spherical coordinate system covers the whole sphere, the coordinate representation of the metric tensor is discontinuous in that coordinate system at the Greenwich Meridian, where the longitude flips from 0 to 360 degrees. So in fact we don't initially have the same formula for the metric tensor everywhere on the sphere, because there will always be a half-great-circle for which it (the formula, not the tensor itself) is undefined. I think you need at least two charts to cover a sphere, and they will have different coordinate representations of the metric tensor.
 
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shereen1 said:
Dear all
I am studying general relativity and i have a question as follow. We have the 2- sphere can be scanned totally by a coordinate system (theta, phi) with the metric tensor written in terms of theta and phi. Now i want to divide the 2-sphere into charts 4 charts then each will have its own coordinate system. Then what will happen for the metric? initially we were having the same formula for the metric for the whole sphere but now shall i say that each chart will have its own metric formula?
Thank you

If you have a chart with coordinates (X,Y), then you will have metric components g_{XX}, g_{XY}, g_{YX}, g_{YY}. These will be related to the metric components for (\theta, \phi) through:

g_{IJ} = \sum_{ij} g_{ij} \dfrac{\partial x^i}{\partial X^I} \dfrac{\partial x^j}{\partial X^J}

where I, J, i, j take values 1 and 2, and where X^1 = X, X^2 = Y, x^1 = \theta, x^2 = \phi.
 
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In an inertial frame of reference (IFR), there are two fixed points, A and B, which share an entangled state $$ \frac{1}{\sqrt{2}}(|0>_A|1>_B+|1>_A|0>_B) $$ At point A, a measurement is made. The state then collapses to $$ |a>_A|b>_B, \{a,b\}=\{0,1\} $$ We assume that A has the state ##|a>_A## and B has ##|b>_B## simultaneously, i.e., when their synchronized clocks both read time T However, in other inertial frames, due to the relativity of simultaneity, the moment when B has ##|b>_B##...

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