General solution to a second order homogeneous differential equation

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SUMMARY

The general solution to the second order homogeneous differential equation y'' - y' = 0 can be expressed as y(x) = c1 cosh(x) + c2 sinh(x), where c1 and c2 are arbitrary real constants. The terms "cosh" and "sinh" refer to hyperbolic cosine and hyperbolic sine functions, respectively, defined as cosh(x) = (e^x + e^(-x))/2 and sinh(x) = (e^x - e^(-x))/2. Both functions satisfy the given differential equation, confirming the validity of the proposed solution.

PREREQUISITES
  • Understanding of second order homogeneous differential equations
  • Familiarity with hyperbolic functions, specifically cosh and sinh
  • Knowledge of differential equation solving techniques
  • Basic calculus concepts, including derivatives
NEXT STEPS
  • Study the derivation of hyperbolic functions and their properties
  • Learn how to solve second order linear differential equations
  • Explore the applications of hyperbolic functions in physics and engineering
  • Investigate the relationship between hyperbolic and trigonometric functions
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Students studying differential equations, mathematicians, and engineers looking to deepen their understanding of hyperbolic functions and their applications in solving differential equations.

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Homework Statement



Find if it is true that the general solution to : y'' - y' = 0, where y(x),
can be written as : y(x) = c1 cosh(x) + c2 sinh(x), where c1 and c2 are real
arbitrary constants.

Homework Equations



differential equation solving

The Attempt at a Solution



I just want to know what the h's mean at the end of sin and cos.
 
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The 'h' means hyperbolic. cosh(x)=(e^x+e^(-x))/2. sinh(x)=(e^x-e^(-x))/2. That's all, it's just an abbreviation for those expressions. Can you show they both satisfy your differential equation?
 

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