- #1

knockout_artist

- 70

- 2

## Homework Statement

[/B]

For differential equation of the form

## y''- y = 0 ##

BC is

## y(1) = B ##

which usually have general solution

## y(x) = C1 e^x + C2 e^{-x} ##

But this manual I am reading always want to go with general solution

## y = C1 \cosh(x) + C2 \sinh( x) ##

I assume that is also acceptable solution.

## Homework Equations

When in this manual boundary condition applied on cosh and sinh in the general solution equation.

It looks like this

## y(1) = B cosh(1-x) + sinh(1- x) ##

BC was

**y(1) = B3. The Attempt at a Solution**

I would think that it should be

## y(1) = B cosh(1) + sinh(1) ##

Why they do (x-1) ?

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