Generalization of hypergeometric type differential equation

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SUMMARY

The discussion centers on the analytical solvability of hypergeometric type differential equations when the parameter λ(s) is a 3rd-degree polynomial. It is established that while Mellin transforms can solve these equations when λ is a constant, the introduction of a polynomial λ complicates the solution process. The participant expresses uncertainty about the analytical solutions for this case and highlights the significance of the polynomial degree restrictions on σ(s) and τ(s) in maintaining the operator's properties.

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  • Understanding of hypergeometric type differential equations
  • Familiarity with Mellin transforms
  • Knowledge of polynomial functions and their degrees
  • Basic concepts of differential operators
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Mathematicians, physicists, and graduate students specializing in differential equations, particularly those interested in hypergeometric functions and analytical methods in mathematical physics.

cg78ithaca
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I am aware that hypergeometric type differential equations of the type:

upload_2018-6-18_19-12-53.png


can be solved e.g. by means of Mellin transforms when σ(s) is at most a 2nd-degree polynomial and τ(s) is at most 1st-degree, and λ is a constant. I'm trying to reproduce the method for the case where λ is not constant, but a 3rd-degree polynomial, and I'm not sure how to solve Mellin-transformed version of the equation above if λ is a polynomial and not a constant, if indeed it is solvable analytically.

Does the equation above have analytical solutions if λ(s) is a 3rd-degree polynomial, and if so, how do I arrive at them?
 

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I played around with equations "similar" to these in graduate school. I would just point out (forgive if this is obvious) if ##\sigma(s)## and ##\tau(s)## are restricted to polynomials of second and first order then the equation viewed as an operator on ##y(s)## sends polynomials of order ##n## into polynomials of order ##n## which I believe is what makes them "special". Letting ##\lambda## be a polynomial in ##s## will break this property.
 

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