Generator Design for 50Hz, 240V

[brenton]

hey, i have a physics quiestion which i am stuck on any help would be much appreciated

you are asked to design a generator to produce the same 50Hz, 240V(rms) as found in a domestic voltage outlet

The generator is made of a single flat coilbeing made to rotate in a uniform magnetic field of strength 0.08T. the coil may be of any surface area and have as many turns as you like, provided the area and number are "reasonable" values. the length of the coil is L, its width is W, and it spins at an angular rate (omega)w = 2Pi.50 rads/s

What values would you choose for thr area of the coil, A, and for the number of turns, N, that will provide this emf.

i have never done physics before so i don't even no what to begin...could comeone please run me though how i would attempt it..
thankyou

 

[geosonel]

hey, i have a physics quiestion which i am stuck on any help would be much appreciated

you are asked to design a generator to produce the same 50Hz, 240V(rms) as found in a domestic voltage outlet

The generator is made of a single flat coilbeing made to rotate in a uniform magnetic field of strength 0.08T. the coil may be of any surface area and have as many turns as you like, provided the area and number are "reasonable" values. the length of the coil is L, its width is W, and it spins at an angular rate (omega)w = 2Pi.50 rads/s

What values would you choose for thr area of the coil, A, and for the number of turns, N, that will provide this emf.

i have never done physics before so i don't even no what to begin...could comeone please run me though how i would attempt it..
thankyou

check here:
https://www.physicsforums.com/showthread.php?t=83812

 

[thepatientmental]

First of all, let's break down the problem into smaller parts. We need to design a generator that produces a 50Hz, 240V output. This means that the generator needs to rotate at a rate of 50 revolutions per second (2Pi x 50 = 100Pi radians per second) and produce an output voltage of 240V.

Now, let's look at the given information. The generator is made of a single flat coil that rotates in a magnetic field. The strength of the magnetic field is 0.08T and the coil can have any surface area and number of turns, as long as they are reasonable values. The length of the coil is L and its width is W.

To find the values for the area of the coil, A, and the number of turns, N, we need to use Faraday's law of electromagnetic induction. This law states that the induced electromotive force (emf) is equal to the rate of change of magnetic flux through a closed loop.

In this case, the magnetic flux is given by the formula B x A x cos(theta), where B is the magnetic field strength, A is the area of the coil, and theta is the angle between the magnetic field and the normal to the coil.

We know that the magnetic field strength is 0.08T and the angle is 90 degrees (since the coil is rotating in a uniform magnetic field). So, the formula becomes B x A x cos(90) = B x A.

Now, to find the emf, we need to multiply this by the angular rate (omega)w. So, the formula becomes emf = B x A x (omega)w.

Since we want an output voltage of 240V, we can set this equal to 240V and solve for A. So, A = 240V/(B x (omega)w).

We also know that the frequency is 50Hz, which means that the angular rate is (omega)w = 2Pi x 50 = 100Pi radians per second. Substituting this into the formula, we get A = 240V/(B x 100Pi).

Now, we can choose a reasonable value for the magnetic field strength, B, and plug it into the formula to find the area, A, of the coil. Let's say we choose B = 0.08T, then the area of the coil would be