1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

EMF and Peak Voltage of a Generator

  1. Feb 7, 2015 #1
    1. The problem statement, all variables and given/known data
    A simple electric generator contains a 30-turn coil of area 6.6 x 10^-4 meters squared. The coil spins in a magnetic field of 0.80 T at a frequency of 60 Hz.

    a) What is the peak output voltage?
    b) How must the number of turns be changed to maintain the same output voltage, but operate at a frequency of 50 Hz.

    2. Relevant equations
    ω = 2πf
    emf/peak voltage= NBωAsinωt

    3. The attempt at a solution

    ω = 2π(60) = 377 rad/s

    emf = NBωAsinωt = 30(0.80T)(377)(6.6x10^-4)sin(377)t

    My problem is that I do not know how/where to obtain the time (t) to finish the calculation. My first assumption is to use t = 1 second, since frequency is in Hz, which is revolutions per second.

    emf = NBωAsinωt = 30(0.80T)(377)(6.6x10^-4)sin(377)(1) = 1.75 V

    Is this correct? If so, then I am sure I can do part b) on my own. Thanks for the help!
     
  2. jcsd
  3. Feb 7, 2015 #2

    rude man

    User Avatar
    Homework Helper
    Gold Member

    If a signal is Asin(wt), what is its amplitude? Does it depend on w or t?
     
  4. Feb 7, 2015 #3
    So I believe I figured it out. At peak voltage, the amplitude sinwt is at its peak too, which is equal to 1. Thanks for the help!
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: EMF and Peak Voltage of a Generator
  1. EMF in a Generator (Replies: 3)

Loading...