A simple generator has a coil with dimensions 1.0 cm x 1.0 cm which
is rotated at 60 Hz in 1.0 T magnetic field. How many windings (turns of
wire) are needed to generate a peak emf of 120 Volts ?
1. emf E = - d (magnetic flux) / dt
2. magnetic flux = (B dot n hat) A
3. emf E for generator(rotating coil/loop) = N B A w(sin wt) where N is number of turns, B is magnetic field, A is area of coil, w is omega = 2 pi f
The Attempt at a Solution
Is it correct to assume the coil is a square coil? since it only gives me those two dimensions..
i used equation 3 above and used A = .01 m(squared), B = 1.0 T , omega w = 2 pi f, f = 60 Hz, and emf E = 120 V
but i don't know what "t" is for sin(wt)... do i even need that part of the equation to solve this problem?
what exactly does "peak emf" mean? does it mean amplitude, in which case i only need NBAw?