Understanding Geodesic Deviation: Solving for Equations (7) to (8)

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The discussion focuses on the transition from Equation (7) to Equation (8) in a geodesic deviation context. Participants highlight the importance of recognizing that certain terms, specifically those involving the small variable χ and its derivatives, can be neglected in the calculations. One user initially struggles with additional terms but later realizes that dropping the product of χ and its derivative simplifies the derivation. The conversation emphasizes the significance of understanding these approximations to clarify the relationship between geodesic equations and tidal forces. Overall, the thread illustrates the collaborative effort to resolve a mathematical challenge in understanding geodesic deviation.
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Originally posted by Arcon
Can someone take a look at

http://wps.aw.com/wps/media/objects/500/512494/supplements/Ch21.pdf

and tell me how they go from Eq. (7) to Eq. (8)? I've tried this and keep getting additional terms.

i took a look at it, and did the calculation. i thought it was pretty straightforward. where did you get stuck? what extra terms do you have?

remember that x is a geodesic. so there is a geodesic equation in x, and it therefore vanishes. and remember that χ is very small; drop any term with more than one χ in it.
 


Originally posted by lethe
i took a look at it, and did the calculation. i thought it was pretty straightforward. where did you get stuck? what extra terms do you have?

remember that x is a geodesic. so there is a geodesic equation in x, and it therefore vanishes. and remember that χ is very small; drop any term with more than one χ in it.

I fingered it out :smile:

One has to drop not only the term &chi*&chi but the term which is the product of &chi and a derivative of &chi. That was what I was missing.
 


Thank you

I believe that I've fingered it out :smile:

One has to drop not only the term χ*χ but the term which is the product of χ and a derivative of χ. That was what I was missing.

Again - thanks for the response

Arcon
 


Originally posted by lethe
i took a look at it, and did the calculation. i thought it was pretty straightforward. where did you get stuck? what extra terms do you have?

remember that x is a geodesic. so there is a geodesic equation in x, and it therefore vanishes. and remember that χ is very small; drop any term with more than one χ in it.

Seems that this small detail (drop term with χdχdT) has always tripped me up in that derivation. I guess I was just blind to it. But now that I know it then the derivation is simple.

Just to make sure I understood the approximation can you check this for me?

http://www.geocities.com/physics_world/gr/geodesic_deviation.htm

I commented on the terms to drop right after Eq. (14) and right after Eq. (15)

Thanks

I don't know how I missed this before but the equation of geodesic deviation clearly shows that tidal forces are velocity dependant!

Arcon
 

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