Geometric Distribution: Finding Specific p Value for Mean Calculation

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Homework Help Overview

The discussion revolves around a geometric distribution problem, specifically focusing on finding the parameter \( p \) given a mean of 0.6. Participants are exploring the relationship between the probability generating function (p.g.f.) and the mean in the context of a random variable representing the number of items bought by customers in a bookshop.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are attempting to understand how to derive the specific value of \( p \) from the given mean and the relationship between \( p \), \( q \), and \( s \) in the context of the p.g.f. and the mean formula.

Discussion Status

Some participants have clarified the definitions of \( p \), \( q \), and \( s \), while others are questioning how to apply these definitions to find the specific value of \( p \) based on the mean provided. There is an ongoing exploration of the implications of the mean in relation to the parameters of the distribution.

Contextual Notes

The problem is constrained by the requirement to find the parameter \( p \) given a specific mean, and the discussion includes clarifications about the roles of the variables involved in the geometric distribution.

umzung
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Homework Statement
The number of items bought by each customer entering a bookshop is a random variable X that has a geometric distribution starting at 0 with mean 0.6.
Find the value of the parameter p of the geometric distribution, and hence write down the probability generating function of X.
Relevant Equations
$$q/(1-ps)$$
I know the p.g.f. of X is $$q/(1-ps)$$ and that the mean is $$p/q$$, but how do I find a specific value for p here?
 
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umzung said:
Homework Statement:: The number of items bought by each customer entering a bookshop is a random variable X that has a geometric distribution starting at 0 with mean 0.6.
Find the value of the parameter p of the geometric distribution, and hence write down the probability generating function of X.
Homework Equations:: $$q/(1-ps)$$

I know the p.g.f. of X is $$q/(1-ps)$$ and that the mean is $$p/q$$, but how do I find a specific value for p here?

What are ##p, q## and ##s## here?
 
PeroK said:
What are ##p, q## and ##s## here?
$$p$$ is the probability, $$q$$ is (1 - probability) and $$s$$ is a dummy variable, not a random variable.
 
umzung said:
$$p$$ is the probability, $$q$$ is (1 - probability) and $$s$$ is a dummy variable, not a random variable.
Okay, so the mean is ##q/p = (1-p)/p##. Do you know the mean in this case?
 
Got it, thanks.
 

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