- #1

songoku

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- Homework Statement
- Please see below

- Relevant Equations
- Poisson Distribution

Exponential Distribution

My attempt:

(i) ##\lambda =3##

(ii)

(a) ##P(N_{2} \geq 1=1-P(N_{2} =0)=1-e^{-6} \frac{(-6)^0}{0!}=0.997##

(b) ##P(N_{4} \geq 3)=1-P(N_{4} \leq 2)=0.999##

(c) ##P(N_{1} \geq 2) = 1-P(N_{4} \leq 1)=0.8##

Do I even understand the question correctly for part (i) and (ii)?(iii) The expectation of exponential distribution is ##\frac{1}{\lambda}## so the answer is ##\frac{1}{3}##?

Thanks