Insights Blog
-- Browse All Articles --
Physics Articles
Physics Tutorials
Physics Guides
Physics FAQ
Math Articles
Math Tutorials
Math Guides
Math FAQ
Education Articles
Education Guides
Bio/Chem Articles
Technology Guides
Computer Science Tutorials
Forums
Intro Physics Homework Help
Advanced Physics Homework Help
Precalculus Homework Help
Calculus Homework Help
Bio/Chem Homework Help
Engineering Homework Help
Trending
Featured Threads
Log in
Register
What's new
Search
Search
Search titles only
By:
Intro Physics Homework Help
Advanced Physics Homework Help
Precalculus Homework Help
Calculus Homework Help
Bio/Chem Homework Help
Engineering Homework Help
Menu
Log in
Register
Navigation
More options
Contact us
Close Menu
JavaScript is disabled. For a better experience, please enable JavaScript in your browser before proceeding.
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an
alternative browser
.
Forums
Homework Help
Precalculus Mathematics Homework Help
Geometric distribution Problem
Reply to thread
Message
[QUOTE="Ray Vickson, post: 4902856, member: 330118"] The first ball always has one of the two colors, so we need only get the probability distribution of number of draws until the opposite color. If the first is white (prob = p) we need the distribution of the number of additional draws until the first black. If the first color is black (prob = q = 1-p) we need the distribution of the number of additional draws until the first white. So, conditioned on the first color, the rest is an ordinary geometric distribution. The overall distribution of number of draws is thus a [B]mixture[/B] of two geometric distributions. See, eg., [url]http://en.wikipedia.org/wiki/Mixture_distribution[/url] for a brief intro to mixtures of distributions (although the article is a bit obscure and hardly introductory). Note that if ##C_1## = color of the first ball (w or b) we have [tex] EN = E(N | C_1= w)\cdot P(C_1=w) + P(N | C_1 = b)\cdot P(C_1 = b) [/tex] and [tex] EW = E(W|C_1=w) \cdot P(C_1 = w) + E(W|C_1 = b) \cdot P(C_1 = b),[/tex] etc. [/QUOTE]
Insert quotes…
Post reply
Forums
Homework Help
Precalculus Mathematics Homework Help
Geometric distribution Problem
Back
Top