Geometric series/geometric progression

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SUMMARY

The discussion focuses on solving a geometric series where the third term is 8 and the sixth term is 128. The formula for the nth term of a geometric sequence, given by a_n = a_1 * r^(n-1), is essential for deriving the equations needed to find the first term (a_1) and the common ratio (r). By substituting the known terms into the formula, two equations can be established: a_1 * r^2 = 8 and a_1 * r^5 = 128. Solving these equations yields the complete geometric series.

PREREQUISITES
  • Understanding of geometric series and sequences
  • Familiarity with the formula for the nth term of a geometric sequence
  • Basic algebra skills for solving equations
  • Knowledge of exponential functions
NEXT STEPS
  • Study the derivation and applications of the geometric series formula
  • Learn how to solve systems of equations involving exponential terms
  • Explore the properties of geometric progressions in mathematical contexts
  • Practice problems involving geometric series to reinforce understanding
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Students studying mathematics, educators teaching algebra, and anyone interested in understanding geometric series and their applications.

Elec68
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I can't figure this out for the life of me:

A geometric series exists with the third term of 8 and the sixth term of 128, what is the geometric series?
 
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Have you tried anything at all? What do you know about geometric series?
 
In particular, do you know the formula for the nth term of a geometric sequence? Use that formula knowing that a3= 8 and a6= 128 to get two equations in the two parameters you need.
 

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