Geometry of Methane: Finding the Distance Between Hydrogen and Carbon Atoms

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SUMMARY

The discussion focuses on calculating the distance between a hydrogen atom (point A) and a carbon atom (point O) in a methane molecule, represented within a cube. The correct formula derived for the distance AO is AO = (e * sqrt(3)) / 2, where e is the length of the cube's edge. The solution involves recognizing triangle AOP as a right triangle and applying the Pythagorean theorem to find the lengths of the sides. The participants clarify the positions of points A, O, and P within the cube to arrive at the solution.

PREREQUISITES
  • Understanding of the Pythagorean theorem
  • Familiarity with geometric concepts related to right triangles
  • Knowledge of three-dimensional geometry and spatial reasoning
  • Ability to interpret geometric diagrams
NEXT STEPS
  • Study the properties of right triangles in three-dimensional space
  • Learn about the geometric representation of molecules, specifically methane
  • Explore advanced applications of the Pythagorean theorem in molecular geometry
  • Investigate the relationship between molecular structure and spatial coordinates
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Chemistry students, geometry enthusiasts, and anyone studying molecular structures or spatial reasoning in three dimensions will benefit from this discussion.

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Homework Statement



In a methane molecule, determine the length of the distance between a hydrogen atom at A and the carbon atom at O (see diagram) in terms of the length of the edge (e) of the cube at four of whose corners the hydrogen atoms rest.

Screen Shot 2016-04-06 at 10.22.09 AM.png


Homework Equations



pythagorean theorem?

3. The Attempt at a Solution


The first part of the problem asks to find AB (see diagram). AB= e(sqrt-2).

The book gives the answer as AO=e(sqrt-3)/2, but I don't know how they got it.

I'm sure this is simple! I'm just not having any luck.

Thanks!
 
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Hi crastinus, you can UPLOAD your file and attach it to your post. Then you can insert it in the text where you want it. Use the UPLOAD button in the lower right corner of the edit pane.
 
Ah. I see it now. Thanks! Edits made.
 
From your image:
upload_2016-4-6_10-22-57.png


Note the plane image of the triangle in question. APO is a right triangle with AO as its hypotenuse. Can you find values for AP and OP?
 
If I'm right that AB= e(sqrt2), then AP=e(sqrt2)/2.

How to find AO? If I knew that this were a certain type of triangle, 45-45 or 30-60, I could determine AO. So, my question is: How can I determine AO knowing only one side and the right angle of triangle AOP. I know the various angles involved, but the point is to get AO in terms of e. That's what I'm not sure how to do.

Thanks!
 
You should be able to determine OP. Where is O located in the cube? Where is P located?
 
Wow. OK. Yes. OP=e/2.

And so, A0=(e/2)^2 + (e(sqrt2)/2)^2, which gives us AO=(e(sqrt3)/2)!

Thanks. Sometimes I just don't see what I'm looking at.
 

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