Bond angle in methane? Have been doing for 1 hr

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Homework Help Overview

The discussion revolves around calculating the bond angle in the methane molecule (CH4), specifically focusing on the geometric arrangement of hydrogen atoms in relation to the carbon atom at the center of a tetrahedron. Participants explore the mathematical relationships between vectors representing the bonds.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of vector mathematics to determine the angle between two C-H bonds, questioning the correct application of the cosine formula for angles between vectors. There is also exploration of the geometric representation of the tetrahedron and its relationship to a cube.

Discussion Status

The discussion is ongoing, with participants attempting to clarify vector components and their magnitudes. Some guidance has been provided regarding the calculation of angles using vector components, but confusion remains about the application of these concepts.

Contextual Notes

Participants mention constraints such as a lack of familiarity with certain vector components and the assumption that each side of the tetrahedron is of unit length. There is also a suggestion to visualize the problem using a cube, which may aid in understanding the spatial relationships involved.

elpermic
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Bond angle in methane? Have been doing for 1 hr!

Homework Statement


In the methane molecule, CH4, each hydrogen atom is at a corner of a regular tetrahedron with the carbon atom at the center. In coordinates where one of the C-H bonds is in the direction of i + j + k, an adjacent C-H bond is in the i - j - k direction. Calculate the angle between these two bonds?



Homework Equations


I know this is a pyramid.



The Attempt at a Solution

 
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If A and B are vectors, then the angle between them is given by
cosθ= A.B/A*B
 


Would that mean that cos theta is equal to the (Ax+Bx) + (Ay+By) divided by the magnitudes of A and B? I think that each side of the pyramid is 1. Is this right?
 


elpermic said:
Would that mean that cos theta is equal to the (Ax+Bx) + (Ay+By) divided by the magnitudes of A and B? I think that each side of the pyramid is 1. Is this right?
No.
cosθ = (AxBx + AyBy + AzBz)/AB, where A and B are the magnitudes of the vectors.
 


So how would I use the method of components to find Ax and Bx, and Ay and By?? I never learned how to do Az and Bz either. I only have one fact that I think, each side is 1.
 


You have expressed bonds is in the direction of i + j + k, an adjacent C-H bond is in the i - j - k direction.
Here coefficient of i, j and k are Ax, Ay and Az. i.e. 1, 1, 1.
Similarly find Bx, By and Bz. Magnitudes of A and B are sqrt(3)
Now find the angle using the formula.
 


It might help to know that a tetrahedron can be embedded in a cube. I think it's far more intuitive to obtain the H-C-H angle by examining the cube.

anim5in1.gif


umm. that wasn't supposed to be spinning, but it's the best I could find.
 
Last edited by a moderator:


I have been trying it out and I still cannot do this
 


Consider if the cube is one unit on a side. The blue line at the top of the cube connects two hydrogen atoms. The length of the line is sqrt(2).

The center of this line lies at the center of a cube face. The center of the cube face is 1/2 unit from the center of the cube. The carbon atom is at the center of the cube.

Draw a picture. Does the line from the center of the cube intersect the blue line at a right angle?
 

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