Proving A*D*B in a Triangle with AB as the Longest Side

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In triangle ABC, where AB is the longest side, it is necessary to prove that the perpendicular from point C to line AB intersects at point D such that A*D*B. The reasoning begins with recognizing that angle ACB is the largest angle due to AB's length. It is established that the perpendicular segment CD is shorter than both sides CB and CA, reinforcing that if A*B*D were true, it would lead to a contradiction where AC would need to be longer than AB. The discussion highlights the importance of understanding the relationships between the sides and angles in a triangle using properties of right triangles and the Pythagorean theorem. Overall, the argument supports the conclusion that A*D*B must hold true given the conditions of the triangle.
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Homework Statement


Let ABC be a triangle, and suppose that AB is the largest side. Prove that the perpendicular from C to the line AB crosses at some point D with A*D*B.

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The Attempt at a Solution


I know that since AB is the largest side, that angle ACB is the largest angle. I also know that CD < CB and CD < CA because a perpendicular is the shortest distance from a point to a line.

I think what I want to say is something like: If we have A*B*D, then we would have CB < CD, which is a contradiction. Is this the right line of thinking, or am I going about this the wrong way?
 
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I think you are thinking along the right general direction. But I don't know if CD is the right segment to focus on. If the order of the points is A*B*D then don't you know AC>AD and AD>AB?
 
Dick said:
I think you are thinking along the right general direction. But I don't know if CD is the right segment to focus on. If the order of the points is A*B*D then don't you know AC>AD and AD>AB?

How do I know that AC > AD from that? If that's true, then I have a contradiction, since AB is supposed to be the longest side, but AC is longer than it.
 
AC is the hypotenuse of a right triangle and AD is a leg. AC>AD. Pythagoras told me.
 
Dick said:
AC is the hypotenuse of a right triangle and AD is a leg. AC>AD. Pythagoras told me.

Duh! :rolleyes: Thanks a lot for your help. :smile:
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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