- #1

RuteNL

- 1

- 0

## Homework Statement

I got a graph with time on the x-axis, and distance on the y-axis. (see attached picture)

I have to calculate the acceleration using only the distance - time graph.

## Homework Equations

I used S(t)=S(0) + V(0) * t + .5 * a * t

^{2}

## The Attempt at a Solution

That gives 1.30=0+0*3.09 + .5 * a * 3.09

^{2}

1.30/(.5/9.5481)=a

a=0.272 m/s

_{2}

But I know the acceleration is 0.42171 m/s

^{2}, because that's the slope of the V,t graph. What am I doing wrong here?

Thanks.

http://alecm.nl/user/ruurd/test/pfhelp.jpg

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