Get Calculus Project Help for Optimization Problem | Can Shape | Problem 3

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SUMMARY

The forum discussion centers on solving an optimization problem related to the dimensions of a can, specifically Problem 3 of a calculus project. The user has differentiated the function 4√3 r² + 2πrh + k(4πr + h) with respect to r, aiming to find the minimum by setting the derivative to zero. The challenge arises from the presence of multiple variables (V, h, r) in the minimized expression, leading to confusion about how to isolate h and V while maintaining the integrity of the optimization process. The user correctly identifies that V is a constant representing the fixed volume of the can, which complicates the differentiation process.

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  • Understanding of calculus concepts, particularly differentiation and optimization.
  • Familiarity with the geometric properties of cylinders, specifically volume and surface area calculations.
  • Knowledge of variable substitution techniques in calculus.
  • Experience with algebraic manipulation of equations involving multiple variables.
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  • Review the principles of optimization in calculus, focusing on critical points and the second derivative test.
  • Study the method of Lagrange multipliers for constrained optimization problems.
  • Explore the relationship between surface area and volume in cylindrical shapes to better understand variable interactions.
  • Practice solving similar optimization problems involving multiple variables and constraints.
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Students studying calculus, particularly those tackling optimization problems, as well as educators seeking to enhance their teaching methods in applied mathematics.

gtcox
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My class is doing an optimization problem, The shape of a can. I have attached a copy of the problem.

I have done problems 1 and 2 and now am stuck on problem 3.
What I've tried so far is to differentiate the function 4sqrt3 r^2 +2Pi rh +k(4Pir +h) with respect to r where h=v/Pir^2. I know that to optimize the function I have to set the derivative equal to zero and solve to find min/max but I have to show that when the expression is minimized it is equal to the third root of volume over the constant k. What baffles me is that all the variables V, h and r are in the minimized expression. How did that happen?
 

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Is V a variable? It looks to me like this problem is asking for the most efficient dimensions for a can of a fixed volume- that is V is a constant. And since you also know that h= V/\pi r^2, you can replace h by that and have only r as a variable.
 
That's what I tried, but when you substitute for h and differentiate the result is in V, r and k. When the expression is minimized it is in terms of V,r,k,and h. I just don't know how all the h got back into the equation along with V. If i set the derivative equal to 0 and solve for V, then replace V with Pi(r^2)(h), the V dissapears. If i don't solve for V then I don't know how to get the h back into the equation. Am I making any sense?
 

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