Calculating Total Energy with Dimensional Analysis | Screenshot Included

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SUMMARY

The discussion centers on calculating total energy using dimensional analysis, specifically involving heat capacity given as 11.3 kJ/(C*g). The user attempted to calculate energy by multiplying heat capacity by the temperature change (7.3 C) and the mass of methane (1.50 g). However, confusion arose regarding the absence of grams in the teacher's solution, which emphasized total energy as energy required per degree multiplied by the number of degrees. The consensus indicates that the original problem may contain errors, particularly in the terminology used for heat capacity.

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  • Understanding of dimensional analysis
  • Familiarity with heat capacity and specific heat capacity concepts
  • Knowledge of calorimetry principles
  • Basic proficiency in energy unit conversions (kJ, Joules)
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  • Learn about the differences between heat capacity and specific heat capacity
  • Research the concept of calorimeter constants and their applications
  • Study dimensional analysis techniques in thermodynamics
  • Explore energy calculations involving moles and mass in chemical reactions
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JessicaHelena
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Homework Statement


Please look at the screenshot.

Homework Equations



dimensional analysis

The Attempt at a Solution


Since the heat capacity is given as 11.3 kJ/(C*g), and energy is measured in Joules (or kJ), I thought to multiply 11.3 by the change in temp (7.3 C) and also 1.50 g of methane.

However, as you can see, what my teacher did is quite different (does not have the grams).

but he explicitly states that total energy = energy required per deg x no. of deg... where'd the grams go then?
Please help me out!
 

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JessicaHelena said:

Homework Statement


Please look at the screenshot.

Homework Equations



dimensional analysis

The Attempt at a Solution


Since the heat capacity is given as 11.3 kJ/(C*g), and energy is measured in Joules (or kJ), I thought to multiply 11.3 by the change in temp (7.3 C) and also 1.50 g of methane.

However, as you can see, what my teacher did is quite different (does not have the grams).
but he explicitly states that total energy = energy required per deg x no. of deg... where'd the grams go then?
Please help me out!
You’re given the SH of the bomb calorimeter. Then it seems to switch to what’s called a calorimeter constant, which is just J/C. The question seems oddly worded and is perhaps just a mistake in the notes?

You might want to email your professor and ask for clarification or wait for another reply here from someone to see something I missed or am misunderstanding myself.
 
My bet is that is a mistake, 11.3 looks like it is intended to be a heat capacity, not a specific heat capacity (note you are not given calorimeter mass which makes the question impossible to solve).
 
I agree with the last two posters that to call it specific heat capacity is unfortunate, it is just a heat capacity (and should not contain g).
But as far as it goes the calculation appears to me correct.
Where have the grams gone? You just need to convert the kJ for that amount of octane in that particular experiment to something of more general value, the kJ per mole octane, or maybe for engineers kJ/Kg.
 
Last edited:

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