# GFORTRANdealing without CONOUT$1. Jun 25, 2013 ### jelanier I have been re-writing several old FORTRAN programs to compile with G77 G95 and GFORTRAN. G77 and G95 have been good to me. I can't say the same for GFORTRAN. The fact that it does not support CONOUT$ is the biggest issue. Some of these old programs liberally use unit 6 and unit 5. When CONOUT$is available, you can simply open unit 6 with file=CONOUT$ to write to the con again.

While it is possible to write to the con by using write(6,xx) a,b , it does not work if unit 6 has already been used. Even if you close(6), you can not write to the con again. the print *,a,b will not work either.

Play with his test code by commenting out lines and you will see what I mean. Is there a solution?

Thanks,

Jim

program test_con
character(10) a,b,c

a="hello"
b="goodbye"

open (6,file="conout.txt")
write (6,10) a,b
C close(6)

C open (6,file="conout$") print *,"hello" write (*,10) a,b 10 format(a10,a10) end program test_con 2. Jun 25, 2013 ### gsal I am not sure I fully understand the problem. First, I read that you re-writing this old programs...why won't you clean them up as you go so they actually work? I have never tried to open unit 6 and I have never used it for myself...as far as I knew, it was reserved for standard out, just like units 5 and 0 are... So, if you are having problems with unit 6 just stay away from it, simple. 3. Jun 26, 2013 ### jelanier So in other words...you don't know the answer. You said :"clean them up as you go so they actually work?" They do work. I don't know what you are talking about with that comment. It just takes more effort with GFORTRAN. Every time you execute a program from the aforementioned compilers, unit 6 is opened. The question is how to initialize unit 6 to con after it has been re-directed to a file. G77 and G95 provide that feature. 4. Jun 26, 2013 ### gsal Well, I may not be a computer expert, but I have been programming happily for a couple of decades and helping other people, too, and I am yet to find a problem I cannot programmed...that is not to say that I have solved all the problems that I have found, but there is more than one way to skin a cat...so... ...while you may not like the answer or advice I have given to you, it would allow you to stop wasting time on that issue and move on... good luck 5. Jun 26, 2013 ### jelanier My point is, if you don't know the answer don't reply. Especially if you are going to be a smart-***. I am a design engineer and have been programming in various languages for 39 years. I don't waste time..I learn and find new ways to resolve issues. Smart-*** replies have no place in technical forums. 6. Jun 26, 2013 ### Mark44 ### Staff: Mentor What version of gfortran are you using? It says here (http://gcc.gnu.org/wiki/GFortran) that conout$ is supported in gfortran v4.5.

7. Jun 26, 2013

### jelanier

Thanks for the reply Mark44. I read that as well while I was searching for a solution. I am running version 4.7.0 on this machine and 4.7 on my Linux Box. I can't remember which version I have on my work computer. One of the versions I had supported CONIN$but not CONOUT$. Surely that was a bug. GFORTRAN has loads of bugs (too numerous to mention here). My favorite bug is when it flags syntax errors in comment lines :)

Thanks again,,

Jim