Gibbs-Duhem Relation/Entropic Equations of State

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SUMMARY

The discussion focuses on the Gibbs-Duhem relation and its application in deriving entropic equations of state as presented in Callen's textbook, specifically in chapter 3.4. The key equations discussed include the ideal gas law (PV = nRT) and internal energy (U = cnRT), leading to the relationships P/T = nR/V and 1/T = cNR/U. The integration of the Gibbs-Duhem relation, d(μ/T) = u d(1/T) + v d(P/T), is highlighted as a crucial step in deriving the equation μ/T as a function of u and v, although some participants express confusion regarding the derivation process.

PREREQUISITES
  • Understanding of the ideal gas law (PV = nRT)
  • Familiarity with thermodynamic potentials, specifically chemical potential (μ)
  • Knowledge of differential calculus as applied to thermodynamic equations
  • Basic concepts of entropy and its relation to state functions
NEXT STEPS
  • Study the derivation of the Gibbs-Duhem relation in detail
  • Explore the implications of entropic equations of state in thermodynamics
  • Investigate the relationship between chemical potential and temperature in various systems
  • Review the mathematical techniques for integrating differential equations in thermodynamics
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Students and professionals in thermodynamics, physicists, and chemists seeking to deepen their understanding of the Gibbs-Duhem relation and its applications in entropic equations of state.

mateomy
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I'm working through Callen (ch. 3.4) right now and I'm trying to follow his explanation of the Gibbs-Duhem relation:

Beginning with the ideal gas characterizations
<br /> PV = nRT<br />
<br /> U = cnRT<br />
there is some rearranging of terms and we are shown the relations
<br /> \frac{P}{T}=\frac{nR}{V}<br />
<br /> \frac{1}{T}=\frac{cNR}{U}<br />
and recognizing the further definitions of n/V \equiv v and N/U \equiv u.
Then Callen states 'from these two entropic equations of state we find the third equation of state'
<br /> \frac{\mu}{T} = \,function\, of\, u,\, v \,\,\,\,\,\,[1]<br />
by integrating the Gibbs-Duhem relation
<br /> d\left(\frac{\mu}{T}\right) = ud\left(\frac{1}{T}\right) + vd\left(\frac{P}{T}\right)<br />

I'm not seeing where he gets [1] from. Is that just a definition? I noticed a few sections before this he defined:
<br /> d\mu = -sdT + vdP<br />
I'm missing something but I don't know what. Just looking for some clarification, thanks.
 
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He says that the integrated version [1] comes from the differential one called Gibbs-Duhem. So your question is actually where Gibbs-Duhem comes from and that should be answered by Callen.
 

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