Give a formula the open unit disk

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SUMMARY

The discussion focuses on deriving formulas for partial derivatives within the open unit disk D = {(x,y)|x² + y² < 1}. For part (a), the sum \(\sum^{\infty}_{n=0} (xy)^{n}\) simplifies to \(\frac{1}{1 - xy}\) under the condition that \(xy < 1\). This is a geometric series application. For part (b), the task involves evaluating the integral \(\int^{y}_{x} e^{-t} dt\) and applying the product rule to find the partial derivative with respect to \(y\).

PREREQUISITES
  • Understanding of geometric series and convergence criteria
  • Familiarity with partial derivatives and the product rule
  • Knowledge of integration techniques, specifically with exponential functions
  • Basic concepts of multivariable calculus
NEXT STEPS
  • Study geometric series convergence and applications in calculus
  • Review the product rule for differentiation in multivariable calculus
  • Practice evaluating integrals involving exponential functions
  • Explore partial derivatives in the context of multivariable functions
USEFUL FOR

Students preparing for exams in calculus, particularly those focusing on multivariable calculus and differential equations. This discussion is beneficial for anyone needing to understand partial derivatives and series within the context of open unit disks.

nhartung
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Homework Statement



In the open unit disk D = {(x,y)|x2 + y2 < 1} give a formula for:

(a) [tex]\frac{\partial \sum ^{inf}_{n=0} (xy) ^{n}}{\partial x}[/tex]

(b) [tex]\frac{\partial (e^{x+y} \int ^{y}_{x} e^{-t} dt)}{\partial y}[/tex]

Homework Equations





The Attempt at a Solution



Ok this is on my exam review sheet and he gave us the solutions to go along with it.. I don't know if I wasn't paying attention in class or what but I don't remember doing anything like this.

His first step for a is [tex]\sum ^{inf}_{n=0} (xy)^{n} = \frac{1}{1 - xy}[/tex] if xy < 1 (But for all (x,y)[tex]\in[/tex] D xy < 1

I'm already confused at this point. Can someone please let me know what is going on here? Thanks
 
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The sum of r^n is 1/(1-r) if |r|<1. Now put r=(xy). It's just a geometric series. For the second one just evaluate the integral and take the partial derivative using the product rule etc. There's nothing really special going on there.
 

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