Given a polynomial p, prove A^2-B^2 = p(1)p(-1)

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SUMMARY

The discussion centers on proving the equation A2 - B2 = p(1)p(-1) for a polynomial p, where A represents the sum of the coefficients of the even powers and B represents the sum of the coefficients of the odd powers. The solution involves expressing A and B in terms of p(1) and p(-1), simplifying the proof significantly. The approach is validated, but participants are encouraged to generalize the proof for an arbitrary number of terms N.

PREREQUISITES
  • Understanding of polynomial functions and their coefficients
  • Familiarity with the concepts of even and odd powers in polynomials
  • Knowledge of polynomial evaluation at specific points, particularly p(1) and p(-1)
  • Basic algebraic manipulation, specifically the difference of squares
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  • Explore the properties of polynomial coefficients in detail
  • Learn about the implications of evaluating polynomials at specific points
  • Study the difference of squares and its applications in algebra
  • Investigate generalizations of polynomial identities for arbitrary terms N
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Students studying algebra, particularly those focusing on polynomial functions, mathematicians interested in polynomial identities, and educators looking for teaching resources on polynomial properties.

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Homework Statement


Given a polynomial p, let A be the sum of the coefficients of the even powers, and let B be the sum of the coefficients of the odd powers. Prove that A^2 - B^2 = p(1)p(-1).

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The Attempt at a Solution


See attached. Can someone please look at my work to see if it is correct. Best!
 

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Your solution is correct but limited. Can you show this to be true for an arbitrary number of terms ##N## without going through all the tediousness of your method? Generous hint: Can you express A and B in terms of P(1) and P(-1)?
 
Well that was a lot easier! Thanks!
 

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