Given Electric Potential Function Find where field is zero.

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Homework Help Overview

The problem involves finding the position where the electric field is zero based on a given electric potential function, V = ax² + bx + c, with specified coefficients for a, b, and c. The context is within the study of electric fields and potentials in physics.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of the electric field as the negative gradient of the potential function, with specific focus on the derivative with respect to x. There are attempts to clarify the correct form of the derivative and its implications for finding where the electric field is zero.

Discussion Status

There is an ongoing examination of the derivative of the potential function, with some participants questioning the accuracy of previous calculations. A correction to the derivative has been suggested, and participants are reflecting on their understanding of the differentiation process.

Contextual Notes

Participants express surprise at making errors in basic differentiation despite familiarity with more complex mathematical concepts. This indicates a potential area of confusion or oversight in foundational calculus skills.

disfunctlguru
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1. The electric potential in a certain region is:
V = ax2 +bx +c

where a = 13V/m2
b = -16V/m
c = 59 V

Determine the postion where the electric field is zero. Answer in units of m.

Homework Equations



E = -[tex]\nabla[/tex]V

The Attempt at a Solution



I know that the Electric Field is the negative gradient of the potential function. I then find that the partials with respect to y and z are zero. Then I find the partial with respect to x is: Ex=-13x+16
Then find the zero to be about 1.23. But it is apparently incorrect. Any help would be appreciated.
 
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disfunctlguru said:
Then I find the partial with respect to x is: Ex=-13x+16
Redo that derivative.
 
Well the actual partial deriv. is 13x-16. Then I took the opposite to be used as the function of E.
 
disfunctlguru said:
Well the actual partial deriv. is 13x-16. Then I took the opposite to be used as the function of E.
Double check that.
disfunctlguru said:
1. The electric potential in a certain region is:
V = ax2 +bx +c
What's the derivative of that function?
 
Thanks, I can't believe I can do some other complex integration etc and mess up a simple deriv... mind blowing.
 

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