Given range and angle - but not time - find initial velocity?

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Homework Help Overview

The discussion revolves around calculating the initial velocity required for a missile to achieve a specified range of 9500 km, while disregarding certain factors such as the missile's boost phase and the curvature of the Earth.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the use of projectile motion equations, particularly considering a launch angle of 45° for maximum range. There are attempts to calculate the initial velocity using the formula R=Vo^2/g*sin(2*45), but results are questioned due to unexpected low values.

Discussion Status

Participants are actively engaging in recalculating their results and questioning the accuracy of their initial attempts. Some guidance is offered regarding the importance of using standard units for calculations, and there is acknowledgment of errors in unit conversion.

Contextual Notes

There is a noted confusion regarding the appropriate equations and units to use, as well as the implications of disregarding certain physical factors in the problem setup.

exi
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Homework Statement



Given a missile with 9500km range, what must its initial velocity be to travel that distance? Disregard issues introduced by the missile's boost phase, and state the velocity as km/h.

(Presumably, the curvature of the planet is to be ignored, as well.)

Homework Equations



Unsure; see below.

The Attempt at a Solution



If a missile is to have maximum range, then its launch angle ought to be 45°. It would also have a symmetrical trajectory and is affected by gravity at -9.8 m/s^2 (or 0.0098 km/s^2 in the terms of this problem).

The first thing that came to mind was to use R=Vo^2/g*sin(2*45) and solve for Vo, but that yielded something ridiculously slow for that long of travel.

I'm rather unsure as to which equation(s) ought to be used to solve such a problem, since everything I can find written in my notes refers to what appear to be slightly different situations.
 
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exi said:
The first thing that came to mind was to use R=Vo^2/g*sin(2*45) and solve for Vo, but that yielded something ridiculously slow for that long of travel.
What did you get?
 
Doc Al said:
What did you get?

I did it the first time without converting acceleration and had 300something km/h, or 186 mph.

The second time with the conversion worked out to like 93.1 km/h, which ... well, a 57 mph missile isn't going to travel 6,000 miles. :mad:
 
You might want to redo your calculation--you're way off. Be sure you use standard units and then convert to km/h.
 
Doc Al said:
You might want to redo your calculation--you're way off. Be sure you use standard units and then convert to km/h.

Yeah, so I am. 9.6488 km in a second sounds more like it (and is correct). Looks like my bad habit of neglecting units in figures bit me in the ass for once.

Thanks again. This place is becoming my home away from physics lecture home, I swear.
 

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