Given the diagram, what is the tension in each string?

In summary: There is the tension T3, which we do not know, and there is the weight mg acting downward. Can you set up an equation that relates T3 and mg?In summary, the conversation involves finding the tension in each string of a system with four masses, each weighing 1kg, and with a given diagram and angles. The solution involves drawing force diagrams for each mass, using the equations ∑Fx=max and ∑Fy=may, and solving for T1 and T2. The conversation also addresses uncertainties about T3 and T4 and prompts the use of an equation relating T3 and mg.
  • #1
laladude
14
0

Homework Statement




Given this diagram and the masses involved, what is the Tension in each string. All masses are 1kg.

Diagram provided

4.jpg


Sorry, the angle for T2 is 10°


Homework Equations





The Attempt at a Solution



I really don't know where to start.
 
Last edited:
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  • #2
For each mass, draw a force diagram.

Then use ∑Fx=max and ∑Fy=may. (And you should know what ax and ay are :wink:)
 
  • #3
Redbelly98 said:
For each mass, draw a force diagram.

Then use ∑Fx=max and ∑Fy=may. (And you should know what ax and ay are :wink:)

okay, so for T1 and T2..

x-dir would be ∑Fx = - T1 cos30 + T2 cos10 = 0

y-dir would be ∑Fy = T1 cos30 + T2 cos10 + -mg = 0

Then solve for T1 = T2 cos10/cos30 = 0

Plug into y-dir eq. (T2 cos10/cos30) cos30 + T2 cos10 = mg

T2 = mg/1.97 which is 4.97.

Then plug T2 to T1. Correct?

Now I am uncertain about T3 and T4..
 
Last edited:
  • #4
laladude said:
okay, so for T1 and T2..

x-dir would be ∑Fx = - T1 cos30 + T2 cos10 = 0
Yes, good.
y-dir would be ∑Fy = T1 cos30 + T2 cos10 + -mg = 0
Almost -- for the y-dir, we use sin instead of cos.
Then solve for T1 = T2 cos10/cos30 = 0
Except for the "=0" part, that is correct.
Plug into y-dir eq. (T2 cos10/cos30) cos30 + T2 cos10 = mg
Yes, except that there should be some sin's in there because of what I said before about the y-direction forces.
T2 = mg/1.97 which is 4.97.

Then plug T2 to T1. Correct?
Yes, that is the idea.
Now I am uncertain about T3 and T4..
Have a look at the forces acting on Mass #3.
 
  • #5
Can you please provide more information about the situation and the forces involved? Without knowing the specific setup and any external forces acting on the system, it is impossible to determine the tension in each string.
 

1. What is tension in physics?

Tension in physics is the pulling force that is applied to an object, usually through a string, cable, or rope. It is a vector quantity, meaning it has both magnitude and direction. Tension is measured in Newtons (N).

2. How is tension different from other forces?

Tension is different from other forces because it is an internal force, meaning it acts within an object or system. Other forces, such as gravity or friction, act on an object from the outside.

3. How is tension calculated?

Tension is calculated using the formula T = F * cos(θ), where T is the tension force, F is the applied force, and θ is the angle between the applied force and the string. This formula assumes that the string is in equilibrium, meaning the forces acting on it are balanced.

4. What factors affect tension?

The amount of tension in a string is affected by the magnitude of the applied force, the angle at which the force is applied, and the length and stiffness of the string. In addition, the weight of the object attached to the string can also affect the tension.

5. How does tension impact the stability of an object?

Tension plays a crucial role in the stability of an object. If the tension in a string is too low, the object may not be held securely and may fall. On the other hand, if the tension is too high, it can cause the object to break or deform. Therefore, it is important to calculate and maintain an appropriate amount of tension to ensure the stability of an object.

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