- #1
mr_coffee
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Hello everyone this may be an easy problem, but I'm confused on what they have given me the problem says:
Find f(x) if y = f(x) satisfies
{dy}/{dx} = 32 yx^{15}
and the y-intercept of the curve y = f(x) is 2.
f(x) = ?
But what does that mean that the y intercept is 2? is that an intial condition? if so what is the value of x? if y = 2? or does that mean y(0) = 2? or does it mean y(2) = 0?
Here is my work:
http://img72.imageshack.us/img72/9646/lastscan8sf.jpg
Any help would be great! thanks! :)
Find f(x) if y = f(x) satisfies
{dy}/{dx} = 32 yx^{15}
and the y-intercept of the curve y = f(x) is 2.
f(x) = ?
But what does that mean that the y intercept is 2? is that an intial condition? if so what is the value of x? if y = 2? or does that mean y(0) = 2? or does it mean y(2) = 0?
Here is my work:
http://img72.imageshack.us/img72/9646/lastscan8sf.jpg
Any help would be great! thanks! :)
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