Gradient function using matrix notation
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What is df = (xTQ + qT)dx supposed to mean?
Using the definition of the derivative Df, I calculated that the matrix of Df (that is, grad(f)) is, is ½(Qx+xQ)+q. If Q is a symmetric matrix, then xQ=Qx and we find your result grad(f)=Qx+q.
Using the definition of the derivative Df, I calculated that the matrix of Df (that is, grad(f)) is, is ½(Qx+xQ)+q. If Q is a symmetric matrix, then xQ=Qx and we find your result grad(f)=Qx+q.
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tiny-tim and quasar987,
Thanks for your replies. The calculus classes I had (l-o-n-g time a go) never used matrix notation, so I'm trying to learn it on my own. I've been using this:
http://www.ee.ic.ac.uk/hp/staff/dmb/matrix/calculus.html#deriv_linear
as a guide and was following the terminology in the link. I'm treating dx as a vector quantity (e.g. dx = [dx1, dx2, ..., dxn]T). I'm just having a hard time deriving the expression for grad f based on the info in the link. Also, sorry, but I don't see where the sum notation leads.
Thanks for your replies. The calculus classes I had (l-o-n-g time a go) never used matrix notation, so I'm trying to learn it on my own. I've been using this:
http://www.ee.ic.ac.uk/hp/staff/dmb/matrix/calculus.html#deriv_linear
as a guide and was following the terminology in the link. I'm treating dx as a vector quantity (e.g. dx = [dx1, dx2, ..., dxn]T). I'm just having a hard time deriving the expression for grad f based on the info in the link. Also, sorry, but I don't see where the sum notation leads.
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hi hotvette! 
eugh! I've never come across that terminology before, and I find it really confusing.
Personally, I'd use some other book.
hotvette said:I've been using this:
http://www.ee.ic.ac.uk/hp/staff/dmb/matrix/calculus.html#deriv_linear
as a guide and was following the terminology in the link.
eugh! I've never come across that terminology before, and I find it really confusing.
Personally, I'd use some other book.
What do you think, quasar987?
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