Gradient of a dot product identity proof?

Click For Summary
SUMMARY

The discussion focuses on proving the vector identity ∇(A·B) = A×(∇×B) + B×(∇×A) + (A·∇)B + (B·∇)A from Griffith's E&M textbook. The user attempted to apply the vector triple product identity A×(B×C) = B(A·C) - C(A·B) but encountered an incorrect result. The conversation highlights the importance of understanding the non-commutative nature of the ∇ operator in vector calculus and suggests that using the Levi-Civita symbol and Kronecker delta could simplify the proof process.

PREREQUISITES
  • Vector calculus fundamentals
  • Understanding of the gradient operator (∇)
  • Familiarity with vector identities
  • Knowledge of the vector triple product identity
NEXT STEPS
  • Study the Levi-Civita symbol and its applications in vector calculus
  • Learn about the Kronecker delta and its role in simplifying vector identities
  • Practice proving vector identities using component-wise analysis
  • Explore advanced vector calculus topics, including curl and divergence
USEFUL FOR

Students of electromagnetism, physics majors, and anyone looking to deepen their understanding of vector calculus and its applications in physics.

Libohove90
Messages
40
Reaction score
0
Gradient of a dot product identity proof?

Homework Statement


I have been given a E&M homework assignment to prove all the vector identities in the front cover of Griffith's E&M textbook. I have trouble proving:

(1) ∇(A\bulletB) = A×(∇×B)+B×(∇×A)+(A\bullet∇)B+(B\bullet∇)A

Homework Equations


(2) A×(B×C) = B(A\bulletC)-C(A\bulletB)


The Attempt at a Solution


I applied the identity in equation (2) to the first two terms on the right hand side of equation (1), and that allowed me to cancel out 4 terms. Yet, I end up with:

∇(A\bulletB) = ∇(A\bulletB)+∇(B\bulletA)

...which I know cannot be correct. How can I prove this identity in a relatively straightforward way? I have seen other pages asking this yet they all involved the use of Levi-Cevita symbols and the Kronecker Delta, which I am trying not to use because we haven't learned them. I would gladly appreciate anyone's effort to help me out.
 
Physics news on Phys.org


The only sensible way I can see is to do it by hand for let's say the <x> component in both sides and show they are the same.
 


I was hoping I can get around the long calculations lol
 


You have to be careful with the ∇ operator in vector identities, as it is not commutative. I think this caused the problem here.
The long calculation will work, and it is sufficient to consider one component.
 


Libohove90 said:
I was hoping I can get around the long calculations lol
I know you wanted avoid them, but it's definitely worth learning about the Kronecker delta and Levi-Civita symbol. Using them makes verifying the identity much easier.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 13 ·
Replies
13
Views
4K
  • · Replies 27 ·
Replies
27
Views
4K
  • · Replies 3 ·
Replies
3
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K