Can vector fields have gradients, and how are they calculated?

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SUMMARY

The discussion clarifies the calculation of gradients in vector fields, specifically addressing the force on a magnetic dipole in a magnetic field. The correct formula for this force is given as F = (m_x ∂/∂x + m_y ∂/∂y + m_z ∂/∂z)B, which expands the dot product of the magnetic moment and the gradient of the magnetic field. Additionally, the alternative formula F = ∇(m · B) is presented as a valid method for calculating the force. This discussion resolves confusion regarding the application of gradients to vector fields.

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  • Understanding of vector calculus
  • Familiarity with magnetic dipoles and magnetic fields
  • Knowledge of the dot product and gradient operations
  • Basic principles of electromagnetism
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Physicists, electrical engineers, and students studying electromagnetism or vector calculus will benefit from this discussion, particularly those interested in the behavior of magnetic fields and forces on dipoles.

wprince007
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The force on a magnetic dipole in a magnetic field is the dot product of the magnetic moment and the gradient of the field B, but gradients are operations done on scalar fields to produce vector fields. How does one calculate the gradient of a vector field if field gradients are only defined for scalar fields?
 
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The formula you're referring to is ## \vec F=(\vec m \cdot \vec \nabla) \vec B ##. Its not the dot product of ## \vec m ## and the gradient of the magnetic field. Its expanded form is ## \vec F=(m_x \frac{\partial}{\partial x}+m_y \frac{\partial}{\partial y}+m_z \frac{\partial}{\partial z})\vec B ##.
You can also use the formula ## \vec F= \vec\nabla(\vec m \cdot \vec B)##.
 
Thanks Shyan...that clears things up. For some reason I wasn't notified of your response; I found this just now as I was trying to see if my query had gotten lost.
 
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