Gram-Schmidt Process: Solve for V & x

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SUMMARY

The discussion focuses on the Gram-Schmidt process applied to the set S = {(1, i, 0), ((1-i), 2, 4i)} to obtain an orthogonal basis and subsequently normalize it for an orthonormal basis. The user initially miscalculates the square-norm of the vector v1, leading to confusion regarding division by zero. The correct calculation shows that ||v1||² equals 2, which is essential for proceeding with the orthogonalization process. The discussion also touches on computing Fourier coefficients as part of the solution.

PREREQUISITES
  • Understanding of the Gram-Schmidt process for orthogonalization
  • Familiarity with complex numbers and their properties
  • Knowledge of inner product spaces and norms
  • Basic concepts of Fourier analysis and coefficients
NEXT STEPS
  • Study the Gram-Schmidt process in detail with examples
  • Learn how to compute inner products and norms for complex vectors
  • Explore the normalization of vectors in inner product spaces
  • Investigate Fourier series and their coefficients in the context of complex functions
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Students and educators in mathematics, particularly those studying linear algebra, complex analysis, and Fourier analysis, will benefit from this discussion.

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Homework Statement



V = span(S) where S = {(1, i, 0), ((1-i), 2, 4i)}, and x = ((3+i), 4i, -4)

Obtain the orthogonal basis, then normalize for the orthonormal basis, and then compute the Fourier coefficients.

Homework Equations



v2 = w2 - (<w2,v1>)(v1)/(||v1||²)

The Attempt at a Solution



So using this above equation, I get ||v1||² to equal zero because 1 + i² = 1 - 1 = 0, thus I'm dividing by zero, so where do I go from here, or am I miscalculating somewhere?
 
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How do you compute the square-norm of a complex number?
 
Ok this is what you did wrong:

||v1||² = v1* . v1 = (1, i, 0)*. (1, i, 0) = 1+(-i)(i)=1+1=2
 

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